Question

(a) Calculate the wavelength of light in vacuum that has a frequency of 5.25 x 1018 Hz. nm (b) What is its wavelength in diamond? nm (c) Calculate the energy of one photon of such light in vacuum. Express the answer in electron volts. eV (d) Does the energy of the photon change when it enters the diamond? O The energy of the photon does not change. The energy of the photon changes

Answer 1

Answer:

Explanation:

wavelength = velocity / frequency

= 3 x 10⁸ /5.25 x 10¹⁸

= .5714 x 10⁻¹⁰

= .05714 x 10⁻⁹

= .05714 nm .

b ) wave length in diamond

= wavelength in air / refractive index of diamond

= .05714 nm / 2.4

= .0238 nm .

c )

energy of one photon = hν where h is plank's constant and ν is frequency

= 6.6 x 10⁻³⁴ x 5.25 x 10¹⁸

= 34.65 x 10⁻¹⁶ J

= 34.65 x 10⁻¹⁶  / 1.6 X 10⁻¹⁹ eV

= 21.65 X 10³ eV .

d )

Energy does not change because its frequency does not change .