Answer:
<h2>
206.67N</h2>
Explanation:
The sum of force along both components x and y is expressed as;

The magnitude of the net force which is also known as the resultant will be expressed as 
To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.
Given the position of the object along the x-component to be x = 6t² − 4;


Similarly,



Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N
By combining blue with yellow light is like combining blue light with red and green light. The result of combining these three primary colors of light is to produce white light.
<h3>What is laundry bluing ?</h3>
Laundry bluing is a product adds a trace amount of blue dye to white fabric during laundering to improve its appearance.
Bluing products in higher concentrations can darken jeans and other blue cloth.
The blue overpowered the yellow to reflect white (at least the appearance of white to the human eye).
Blue and yellow are complementary colors that combine to reflect white, Fabrics.
Here,
Yellow light is a combination of red and green light. So combining blue with yellow light is like combining blue light with red and green light. The result of combining these three primary colors of light is to produce white light.
Learn more about White light here:brainly.com/question/16317768
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(a) The velocity of the object on the x-axis is 6 m/s, while on the y-axis is 2 m/s, so the magnitude of its velocity is the resultant of the velocities on the two axes:

And so, the kinetic energy of the object is

(b) The new velocity is 8.00 m/s on the x-axis and 4.00 m/s on the y-axis, so the magnitude of the new velocity is

And so the new kinetic energy is

So, the work done on the object is the variation of kinetic energy of the object:
Answer:
velocity
Explanation:
because the si unit of mass is kg, velocity is m/s, acceleration is m/S2 , moment is kgm2/s . so 5 is given as velocity.
Answer:
The force exerted by the floor is 80 N.
Explanation:
Given that,
Mass of ball = 0.5 kg
Velocity= 4 m/s
Time t = 0.05 s
When the ball rebounds then the kinetic energy is

Where, m = mass of ball
v = velocity of ball
Put the value into the formula


The average force exerted by the floor on the ball = change in kinetic energy over collision time


Hence, The force exerted by the floor is 80 N.