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vazorg [7]
3 years ago
8

If you increase the surface area of a rock, how will it affect the rate at which it weathers? a. It will weather more quickly. b

. It will have no effect because surface area is not a factor in weathering. c. It will weather more slowly. d. It will have no effect because a rock does not have a surface area. Please select the best answer from the choices provided A B C D
Physics
1 answer:
scoundrel [369]3 years ago
6 0

a. It will weather more quickly.

Because more the surface area, more the friction and more the weathering

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While john is traveling along a straight interstate highway, he notices that the mile marker reads 260. John travels until he re
sasho [114]

Answer:

65 miles

Explanation:

The distance travelled till 150 miles is

260 - 150 = 90

But as he walks back although his distance increase his displacement from initial point decrease.

Distance moved from 150 mile post to 175 mile post is

175 - 150 = 25

As he walks backwards in second time in consideration with first time to calculate the displacement we need to substract 90 from 25,

So displacement is 65 miles

8 0
4 years ago
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A

Explanation:

4 0
3 years ago
Explain why the rate of diffusion of a gas decreases with decrease in temperature​
Ivenika [448]

Temperature: Higher temperatures increase the energy and therefore the movement of the molecules, increasing the rate of diffusion. Lower temperatures decrease the energy of the molecules, thus decreasing the rate of diffusion. Solvent density: As the density of a solvent increases, the rate of diffusion decreases.

7 0
3 years ago
Mendeleev gave the name eka-aluminum to an A. compound containing aluminum. B. mixture of aluminum and an unknown element. C. un
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Answer: C. unknown element he predicted would have properties similar to those of aluminum.

Explanation: Mendeleev arranged the elements in order of increasing atomic masses. He left spaces for the elements that were predicted to exist, but were not discovered.

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5 0
3 years ago
Read 2 more answers
A chamber fitted with a piston can be controlled to keep the pressure in the chamber constant as the piston moves up and down to
frutty [35]

The work done on the gas is  37J as the piston compresses it from 1.00 L to 0.633 L.          

<u>Explanation</u>:

<u>Given</u>:

Ideal gas temperature is 298 K

Atm=1.00

The piston compresses from 1.00 L to 0.633 L.

<u>To Find</u>:

The Work  done on the gas

<u>Formula</u>:

W=P(V2 -V1)

where W is the work done on the gas,

P is the pressure of the chamber,

V2 is the second volume of the chamber,

V1 is the first volume of the chamber.

<u>Solution</u>:

         W=P(V2 -V1)

Pressure P is 1 and V2 is 1 and V1 is 0.633

W=(1×10^5)(1-0.633)×10^-3

W=37J

Therefore the work done on the gas is 37J.        

4 0
4 years ago
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