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vazorg [7]
3 years ago
8

If you increase the surface area of a rock, how will it affect the rate at which it weathers? a. It will weather more quickly. b

. It will have no effect because surface area is not a factor in weathering. c. It will weather more slowly. d. It will have no effect because a rock does not have a surface area. Please select the best answer from the choices provided A B C D
Physics
1 answer:
scoundrel [369]3 years ago
6 0

a. It will weather more quickly.

Because more the surface area, more the friction and more the weathering

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You are on a 4 m high ladder and throw a ball upwards at 12 m/s. It lands on the ground below the ladder.
Gelneren [198K]

a) 2.75 s

The vertical position of the ball at time t is given by the equation

y= h+ut-\frac{1}{2}gt^2

where

h = 4 m is the initial height of the ball

u = 12 m/s is the initial velocity of the ball (upward)

g = 9.8 m/s^2 is the acceleration of gravity (downward)

We can find the time t at which the ball reaches the ground by substituting y=0 into the equation:

0 = 4 + 12t - 4.9 t^2

This is a second-order equation. By solving it for t, we find:

t = -0.30 s

t = 2.75 s

The first solution is negative, so we discard it; the second solution, t = 2.75 s, is the one we are looking for.

b) -15.0 m/s (downward)

The final velocity of the ball can be calculated by using the equation:

v=u-gt

where

u = 12 m/s is the initial (upward) velocity

g = 9.8 m/s^2 is the acceleration of gravity (downward)

t is the time

By subsisuting t = 2.75 s, we find the velocity of the ball as it reaches the ground:

v=12 -(9.8)(2.75)=-15.0 m/s

And the negative sign means the direction is downward.

7 0
3 years ago
A soccer player icks a rock horizontally off a 40m high cliff into a pool f water if the player hears the sound of the splash s
Semenov [28]

Answer:

v = 9.936 m/s

Explanation:

given,

height of cliff = 40 m

speed of sound = 343 m/s

assuming that time to reach the sound to the player = 3 s

now,

time taken to fall of ball

t = \sqrt{\dfrac{2s}{g}}

t = \sqrt{\dfrac{2\times 40}{9.8}}

t = 2.857 s

distance

d = v  x t

d = v x 2.875

time traveled by the sound before reaching the player

t_0 = t - t_{fall}

t_0 = 3 - 2.875

t_0 = 0.143 s

distance traveled by the wave in this time'

r = 0.143 x 343

r= 49.05 m

now,

we know.

d² + h² = r²

d² + 40² = 49.05²

d =28.387 m

v x 2.875=28.387 m

v = 9.936 m/s

7 0
3 years ago
This shot is made while your body is not directly facing the basket<br><br><br> (P.E. Sub)
Phoenix [80]
The correct answer is hook shot
8 0
2 years ago
A process occurs in which a system's potential energy increases while the environment does work on the system.
iogann1982 [59]
Ok, now what do you want to know about it?
4 0
3 years ago
A block of weight w sits on a frictionless inclined plane, which makes an angle theta with respect to the horizontal, as shown.
zavuch27 [327]

Answer:

a.

Explanation:

6 0
3 years ago
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