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vazorg [7]
3 years ago
8

If you increase the surface area of a rock, how will it affect the rate at which it weathers? a. It will weather more quickly. b

. It will have no effect because surface area is not a factor in weathering. c. It will weather more slowly. d. It will have no effect because a rock does not have a surface area. Please select the best answer from the choices provided A B C D
Physics
1 answer:
scoundrel [369]3 years ago
6 0

a. It will weather more quickly.

Because more the surface area, more the friction and more the weathering

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As ice melts, more sunlight is absorbed. As more sunlight is absorbed, the atmosphere heats up. As the atmosphere heats up, more
Ne4ueva [31]

Answer: Conduction

Explanation: As ice melts,more sunlight is absorbed,as more sunlight is absorbed,the atmosphere heats up,as the atmosphere heats up,more ice melts. This whole process is known as CONDUCTION.

Conduction occurs when there is different temperature between two materials, when there exist a transfer energy(i.e transfer from higher-energy atoms in the hot region to the lower-energy atoms in the cold region). When the atmosphere is heated up due to sunlight,there is a rise in temperature which makes the ice to melt due to transfer of warmth it absorbed from sunlight.

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A proton moves with a speed of 1.00 x 106 m/s perpendicular to a magnetic field, B. As a result, the proton moves in circle of r
Softa [21]

Answer:

0.0109 m ≈ 10.9 mm

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proton speed = 1 * 10^6 m/s

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<u>determine the radius of the circle in which an electron would move </u>

we will apply the formula for calculating the centripetal force for both proton and electron ( Lorentz force formula)

For proton :

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For electron:

re = Me*V/ qE * B -------- ( 2 )

Next: take the ratio of equations 1 and 2

re / rp = Me / Mp                                 ( note: qE = qP = 1.6 * 10^-19 C )

∴ re ( radius of the electron orbit )

= ( Me / Mp ) rp

= ( 9.1 * 10^-31 / 1.67 * 10^-27 ) 20

= ( 5.45 * 10^-4 ) * 20

= 0.0109 m ≈ 10.9 mm

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16-N because 20-4=16

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