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3 years ago

If the weight of an object of mass "m" is "mg," then the weight of an object of mass "2m" is

2 answers:

6 0

C

because formula for weight is mass of object (m) multiplied by gravitational acceleration (g).......if mass is 2m then weight will become 2mg.......there is no change in (g)......never

k0ka [10]3 years ago

4 0

Answer: Option (C) is the correct answer.

Explanation:

The relation between mass and weight is as follows.

Weight = mass × g

where, g= gravitational force = $9.81 m/s^{2}$

For mass = 2m, calculate the weight as follows.

Weight = mass × g

= 2m × g

= 2mg

This means that when mass of object becomes 2m then its weight will also become 2mg.

Therefore, we can conclude that if the weight of an object of mass "m" is "mg," then the weight of an object of mass "2m" is 2mg.

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2 years ago

Where are the reproductive parts of a plant located?

Mkey [24]

Answer:

<h2>Flower </h2>

Explanation:

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1 year ago

Read 2 more answers

An underwater scuba diver sees the Sun at an apparent angle of 43.0° above the horizontal. What is the actual elevation angle of

Inessa05 [86]

Answer:

The actual elevation angle is 12.87 degrees

Explanation:

In the attachment you can clearly see the situation. The angle of elevation as seen for the scuba diver is shown in magenta, we conclude that $\theta_2=90-43=47$ .

Using Snell's Law we can write:

$n_1\sin(\theta_1)=n_2\sin(\theta_2)$

$\implies \sin(\theta_1)=\frac{n_2}{n_1}\sin(\theta_2)$ ,

Let's approximate the index of refraction of the air (medium 1 in the picture) to 1.

We thus have:

$\sin(\theta_1)=n_2\sin(\theta_2)=1.333\sin(47)$

$\implies\theta_1=\arcsin[n_2\sin(\theta_2)]=\arcsin[1.333\sin(47)]\approx 77.13$ . Calling $\alpha$ the actual angle of elevation, we get from the picture that $\alpha=90-77.13=12.97$

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2 years ago

How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?

ICE Princess25 [194]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

$W = P\Delta V$

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

$W = P(0\ m^3)\\$

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2 years ago

The average intensity of sunlight at the top of the earth's atmosphere in 1390 w/m2. what is the maximum energy that a 34-m x 46

slavikrds [6]

Panel surface area =34m×46m=1,564m^2
total power =1564m^2×1390w/m^2
=2173960watts
now you must calculate total energy.
Energy = power×Time
However time must be in seconds so we multiply 2hrs×60min×60s=7200seconds
7200s×2173960w =15,652,512,000 joules of energy

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2 years ago