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Orlov [11]
3 years ago
13

If the weight of an object of mass "m" is "mg," then the weight of an object of mass "2m" is

Physics
2 answers:
andre [41]3 years ago
6 0
C

because formula for weight is mass of object (m) multiplied by gravitational acceleration (g).......if mass is 2m then weight will become 2mg.......there is no change in (g)......never

k0ka [10]3 years ago
4 0

Answer: Option (C) is the correct answer.

Explanation:

The relation between mass and weight is as follows.

                 Weight = mass × g

where,    g= gravitational force = 9.81 m/s^{2}

For mass = 2m, calculate the weight as follows.

             Weight = mass × g

                          = 2m × g

                          = 2mg

This means that when mass of object becomes 2m then its weight will also become 2mg.

Therefore, we can conclude that if the weight of an object of mass "m" is "mg," then the weight of an object of mass "2m" is 2mg.

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Answer:

The charge on the oil drop is 3e

Explanation:

F = qE

Where;

F is the applied force in Newton

E is the electric field potential N/C

q is charge in C

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Radius, r = 1.362 μm = 1.362 X 10⁻⁶ m

density, ρ = 0.888 g/cm³ = 0.888 X 10³ kg/m³

Electric field potential = 1.92 ✕ 10⁵ N/C

F =mg

mass of the oil drop = density, ρ  X volume of the oil drop

volume of the oil drop (spherical) =  (4/3)πr³ = 1.3333π(1.362 X 10⁻⁶)³

⇒ volume of the oil drop = 10.584 X 10⁻¹⁸ m³

mass of the oil drop = 0.888 X 10³ (kg/m³) X 10.584 X 10⁻¹⁸ (m³)

⇒ mass of the oil drop = 9.399 X 10⁻¹⁵ kg

⇒ F =mg = 9.399 X 10⁻¹⁵ kg X 9.8 = 9.21 X10⁻¹⁴ N

F = qE

q = F/E

q = (9.21 X10⁻¹⁴)/(1.92 ✕ 10⁵) = 4.797 X 10⁻¹⁹ C

In terms of e

1e = 1.6 X10⁻¹⁹ C

=  (4.797 X 10⁻¹⁹ C)/(1.6 X10⁻¹⁹ C) = 3e

Therefore, the charge on the oil drop is 3e

7 0
2 years ago
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