Cumulonimbus - it is a dense cloud Carried by powerful air currents usually in the idea of a storm is coming.
Answer:
1. a) 0,18
2. e) The reaction proceeds to the left, forming more BrCl(g).
Explanation:
1. In a gas reaction as:
2SO₂(g) +O₂(g) ⇄ 2SO₃(g)
it is possible to convert kp to kc using:
kp = kc (RT)^Δn
Where kp is gas equilibrium constant, kc is equilibrium constant (13), R is gas constant (0,082atmL/molK), T is temperature (900K), and Δn is number of moles of gas products - number of moles of gas reactants (That is 2 - (2+1) = -1). Replacing:
kp = 13×(0,082atmL/molK×900K)^-1
<em>kp = 0,18</em>
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2. Based on Le Chatelier's principle, the change in temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system. For the reaction:
2 BrCl(g) ⇄ Br₂(g) + Cl₂(g).
The addition of 0,050M of each compound cause <em>the reaction proceeds to the left, forming more BrCl(g)</em> because based on the reaction, you need two moles of BrCl per mole of Br₂(g) and Cl₂(g) to keep the system in the same. But you are adding the same proportion of moles of each compound.
I hope it helps!
I can’t answer the question sorry. I don’t know what the equation is
Answer: When the reaction reaches equilibrium, the cell potential will be 0.00 V
Explanation:
Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.
The equilibrium is dynamic in nature and the reactions are continuous in nature. Rate of forward reaction is equal to the rate of backward reaction.
The standard emf of a cell is related to Gibbs free energy by following relation:
The Gibbs free energy is related to equilibrium constant by following relation:
For equilibrium 
Thus 
Thus When the reaction reaches equilibrium, the cell potential will be 0.00 V
