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3 years ago

Grade 8 Science

Chemistry

2 answers:

Anna007 [38]3 years ago

5 0

It depends on the object but most objects that don't use energy would stay the same

timofeeve [1]3 years ago

3 0

It’s energy will increase

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What element has 3 valance electrons and 4 energy levels

Vanyuwa [196]

Answer:

gallium

Explanation:

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4 years ago

What element is this? How do you know? (Page 495 and Periodic Table Pages 500-501)

vfiekz [6]

Helium (He)

Explanation:

In the picture we see the following elementary particles:

2 electrons - the two spheres with negative charge which orbit around the nucleus

2 protons - the two spheres with positive charge in the nucleus

2 neutrons - the two spheres with no charge in the nucleus

The element will be Helium (He), because it have the atomic number 2 and the mass number 4, which means it contains 2 electrons, 2 protons and 2 neutrons.

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4 years ago

Please help this is a test you in5 minutes I really need help I’ll give 10 points

kondaur [170]

Answer:

net force is 0

Explanation:

logccccccccccccccccc

3 0

3 years ago

Read 2 more answers

4. The cloud of interstellar dust and gas that forms a star is known as

Ede4ka [16]

It's called a nebula or nebulae (plural). They are not only massive clouds of dust, hydrogen and helium gas, and plasma; they are also often “stellar nurseries” – i.e. the place where stars are born.

6 0

3 years ago

the length of a string is 16cm.Its length becomes 20cm when supporting a weight of 5N.Calculate the length of the string when su

guapka [62]

Answer:

Explanation:

According to hooks law "provide the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force F"

$F= ke$

where F= applied force

k= spring constant

e= extension

Given data

length of string l = 16cm

extension e = 20-16= 4cm

applied force = 5N

we need t o first calculate the spring constant k

apply the formula

$F= ke$

$5=k*4\\k= \frac{5}{4} \\k= 1.25N/cm$

we can now calculate the extension of the string when supporting a 6N weight

$F= ke\\6=1.25*e\\e= \frac{6}{1.25} \\e= 4.8cm$

The length of the string when supporting a 6N weight is

$= length+ extension\\= 16+4.8\\= 20.8cm$

<em>COMMENT </em><em>:According to the analysis an extra weight of 1N will cause add 0.8cm to the length of the string</em>

4 0

3 years ago