Answer: 37 protons, 48 neutrons, and 36 electrons.
Explanation: I assume "Revision" is Rubidium. It is atomic number 37, so it has 37 protons. It's atomic mass is 85, so it has an average of (85-37) = 48 neutrons. It has a charge of +1, so one electron of the original 37 has left.
Answer:
26.73 mg.
Explanation:
- Firstly, we can calculate the no. of moles of magnesium chlorate (Mg(ClO₃)₂):
no. of moles of magnesium chlorate (Mg(ClO₃)₂) = mass/molar mass = (72.03 mg)/(191.21 g/mol) = 0.377 mmol.
<em>Every 1.0 mole of magnesium chlorate (Mg(ClO₃)₂) contains 2.0 moles of Cl.</em>
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∴ The no. of moles of Cl in magnesium chlorate (Mg(ClO₃)₂) = 2(0.377 mmol) = 0.754 mmol.
∴ The mass of Cl are found in 72.03 mg of magnesium chlorate (Mg(ClO₃)₂) = (no. of moles of Cl)(atomic mass of Cl) = (0.754 mmol)(35.453 g/mol) = 26.73 mg.
With what KClO3 reacts with if it is by temperature
2KClO3===》KCl + KClO + O2
Answer:
When there is less carbon (in the form of carbon dioxide) in abiotic matter, less carbon is available for producers making energy storage molecules. When there is more sunlight, producers can make more energy storage molecules from the carbon in carbon dioxide.
Hope this helps.
Answer:
32.73%
Explanation:
To solve this problem, first find the molar mass of Al(OH)₃.2H₂O
Atomic mass of Al = 27g/mol
O = 16g/mol
H = 1g/mol
Molar mass = 27 + 3(16 + 1) + 2(2(1) + 16)
= 27 + 51 + 36
= 114g/mol
Percentage composition = 
x 100 = 32.73%
