Best Answer:<span> </span><span>LiCl
Cl and Li
glucose
BeF2
last question answer 3 strong electrostatic requires a lot of energy
does this help though??</span>
Answer:
C
Explanation:
u can't touch a chemical with bare skin
Answer:
At -13
, the gas would occupy 1.30L at 210.0 kPa.
Explanation:
Let's assume the gas behaves ideally.
As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

where
and
are initial and final pressure respectively.
and
are initial and final volume respectively.
and
are initial and final temperature in kelvin scale respectively.
Here
,
,
,
and
Hence 



So at -13
, the gas would occupy 1.30L at 210.0 kPa.
Answer:
Carbs,lipids,proteins,nuclei acids
Explanation:
Uranium is in the "f" block, because it's external electron configuration is