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Vlada [557]
3 years ago
9

The element with 8 electrons in its 3d sub level is what?

Chemistry
1 answer:
DochEvi [55]3 years ago
8 0
The answer is nitrogen
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What would happen if an aluminum wire were dipped dipped into a solution of tin (II) sulfate?
NeX [460]
When you add aluminum to a solution of tin (II) sulfate, the next reaction will happen:
3Al (s) + 2SnSO4 (aq) → Al3(SO4)2 (aq) + 2Sn (s)
Aluminum wire will dissolve, while tin will precipitate.

This can be proven by a standard potential for both half-reactions:
Sn2+ + 2e → Sn      E = -0.14 V
Al → Al3+ + 3 e       E = +1.66 V

The overall potential is positive (+1.66 V + (-0.14 V) = +1.52 V), which is a proof that this reaction will proceed spontaneously.
6 0
3 years ago
Correct answer please, I need it before 12:07
timofeeve [1]

Answer:

answer of first question is <u>Chlorine</u>

answer of second question is <u>Group </u><u>1</u><u>4</u>

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u></h3>
7 0
3 years ago
A 0.500-g sample of chromium metal reacted with sulfur powder to give 0.963 g of product. Calculate the empirical formula of the
IgorC [24]

Answer: The empirical formula for the given compound is Cr_2S_3

Explanation : Given,

Mass of product = 0.963 g

Mass of Cr = 0.500 g

Mass of S = 0.963 g  - 0.500 g = 0.463 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Cr =\frac{\text{Given mass of Cr}}{\text{Molar mass of Cr}}=\frac{0.500g}{52g/mole}=0.00962moles

Moles of S = \frac{\text{Given mass of S}}{\text{Molar mass of S}}=\frac{0.463g}{32g/mole}=0.0145moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00962 moles.

For Cr = \frac{0.00962}{0.00962}=1

For S = \frac{0.0145}{0.00962}=1.5

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of Cr : S = 1 : 1.5

The ratio of Cr : S = 2 : 3

Step 3: Taking the mole ratio as their subscripts.

The ratio of Cr : S = 2 : 3

Hence, the empirical formula for the given compound is Cr_2S_3

8 0
4 years ago
Which two systems first respond to burning your finger?
Bess [88]

Answer:

B. is my guess

I'm sorry if I'm wrong

God bless :)

7 0
3 years ago
Read 2 more answers
Which one of the following is an oxidation-reduction reaction?
kupik [55]

Answer:

CH4 + 2 O2 --> CO2 + 2 H2O

Explanation:

CH4 + 2 O2 --> CO2 + 2 H2O is the only reaction where an element (oxygen) undergoes a change in oxidation state. In this reaction oxygen changes disproportionately to O⁻². That is ...

O₂ → CO₂ + 4e⁻ ==> oxidation

<u>O₂ + 4e⁻  →  H₂O ==> reduction </u>

2O₂ + 4e⁻  →  CO₂ + H₂O + 4e⁻  ==> Net oxidation-reduction

=>  4e⁻ gained by one mole O₂ in formation of CO₂ = 4e⁻ lost by the other mole O₂ in forming H₂O.

Then...

Including CH₄ (whose elements do not undergo changes in oxidation states) requires doubling reaction to balance by mass thus giving ...

2CH₄ + 2O₂ + 8e⁻  →  2CO₂ + 2H₂O + 8e⁻

Cancelling 8 reduction electrons on left with 8 oxidation electrons on right gives...

2CH₄ + 2O₂  →  2CO₂ + 2H₂O

7 0
3 years ago
Read 2 more answers
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