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kondaur [170]
3 years ago
6

A spaceship ferrying workers to moon base i takes a straight-line path from the earth to the moon, a distance of 384000 km. supp

ose it accelerates at an acceleration 19.9 m/s2 for the first time interval 14.7 min of the trip, then travels at constant speed until the last time interval 14.7 min , when it accelerates at − 19.9 m/s2 , just coming to rest as it reaches the moon. part a what is the maximum speed attained?
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0
You have to assume something about the starting speed. I will take it to be 0 although you know that isn't so.

t = 14.7 min = 14.7 min *[ 60 s / 1 min] = 882 seconds.
vi = 0 m/s
a = 19.9 m/s^2
vf = ???

Formula
=======
a = (vf - vi)/t

Substitute and solve
===============
19.9 = (vf - 0)/882 
19.9 * 882 = vf
vf = 17552 m/s

That seems large. However the time is very long, so you should expect the final velocity to be large.

From your givens, you have three sig digs so the answer is
1.76 * 10^4 m/s

 
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You are standing 30 m from a window that is 30 m off the ground. Your friend tries to toss you something, but only throws it str
pochemuha

Answer:

minimum initial velocity is 21.35 m/s

Explanation:

given data

distance S = 30 m

height h = 30 m

maximum acceleration a = 2 m/s²

to find out

minimum initial velocity that your friend could have thrown the object to enable you to catch

solution

first we get here time with the help of second equation of motion

time = \sqrt{\frac{2h}{a} }  ..................1

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