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eduard
3 years ago
9

Clark has 7 and 1 over 2 feet of wire. Part A: How many 3 over 4 foot pieces can Clark cut from the 7 and 1 over 2 feet of wire?

Show your work. (5 points) Part B: Using the information in Part A, interpret the meaning of the quotient in terms of the two fractions given. (5 points)
Mathematics
1 answer:
uysha [10]3 years ago
6 0

Answer: 7 1/2 divided by 3/4 is 10

Step-by-step explanation:

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HELP PLEASE
Hoochie [10]
If you had values instead of algebraic expressions, you would find the area of the patio and subtract that from the area of the yard. Even though you don't have values, you can still find the area and subtract by expanding and simplifying:
(8x + 2)(6x + 3)
8x × 6x = 48x²
8x × 3 = 24x
2 × 6x = 12x
2 × 3 = 6
So you get 48x² + 36x + 6 as your area of the yard

(x + 5)(3x + 1)
x × 3x = 3x²
x × 1 = x
5 × 3x = 15x
5 × 1 = 5
So the area of the patio is 3x² + 16x + 5

(48x² + 36x + 6) - (3x² + 16x + 5)
48x² - 3x² = 45x²
36x - 16x = 20x
6 - 5 = 1

So your answer is D. 45x² + 20x + 1. I hope this helps!

6 0
2 years ago
Please help ( the function table)
Norma-Jean [14]
Hope this will help

8 0
3 years ago
HELP ASAP PLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLS
notka56 [123]

Answer:

15/6

Step-by-step explanation:

5 0
2 years ago
Flying fish use their pectoral fins like airplane wings to glide through the air. Suppose a flying fish reaches a maximum height
GrogVix [38]

The flight is in the shape of a parabola with a vertex 5 feet above the water and  1/2 * 33 = 16.5 feet horizontally from the point of leaving the water

y = a(x - h)^2 + k

where  (h,k)  is the vertex of the  parabola and here it is (5 , 16.5), so we have the function:-

y = a(x - 16.5)^2 + 5

when x = 0 y = 0  so

0 = a(-16.5)^2 + 5

which gives a = -0.018365

So our function for the flight path is

y = -0.018365(x - 16.5)^2 + 5     Answer



7 0
2 years ago
Read 2 more answers
Площадь параллелограмма сторона которого равна 4,7 см а проведённая к ней высота 3,1​
Finger [1]

Answer:

im sorry but i dont understand

5 0
3 years ago
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