Answer:
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
(<em>v </em>is the final velocity, <em>u</em> is the initial velocity, <em>t </em>is the time).
The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:
Substitute the values into the formula.
Subtract in the numerator.
Divide.
The acceleration of the object is <u>42.8 meters per square second.</u>
Answer:
After 4 s of passing through the intersection, the train travels with 57.6 m/s
Solution:
As per the question:
Suppose the distance to the south of the crossing watching the east bound train be x = 70 m
Also, the east bound travels as a function of time and can be given as:
y(t) = 60t
Now,
To calculate the speed, z(t) of the train as it passes through the intersection:
Since, the road cross at right angles, thus by Pythagoras theorem:
Now, differentiate the above eqn w.r.t 't':
For t = 4 s: