Solution: From the given question, we shall find the vector quantity among the
(A) Time , (B) Velocity, (C) Distance , (D) Speed
Concept: <u>Vector Quantity: </u>All those physical quantities which have magnitude as well as specific directions, are called Vector Quantities.
Here, Time, Distance and Speed have only magnitude but have no directions so they will be scalar quantities.
Now, <u>Velocity:</u> It is defined as the change in displacement per unit time. Since the change in the displacement will be in particular direction only. Hence, velocity will be the vector quantity.
Hence, the option (B) Velocity will be the correct option.
Answer:
mu = 0.56
Explanation:
The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

v: final speed = 0m/s (the car stops)
v_o: initial speed in the interval of interest = 60km/h
= 60(1000m)/(3600s) = 16.66m/s
x: distance = 25m
BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

Furthermore, you use the relation between the friction force and the friction coefficient:

hence, the friction coefficient is 0.56
Answer:The term atomic number, conventionally denoted by the symbol Z, indicates number of protons present in the nucleus of an atom, which is also equal to the number of electrons in an uncharged atom. The number of neutrons is represented by the neutron number (N)
Explanation:
Answer:
9.412 rad/s.
Explanation:
Velocity is the rate of change of an object's position.
V = x/t
Where x is the distance in m
= 2.4 m
t is time taken in s
= 8.5 s
V = 2.4/8.5
= 0.2824 m/s.
Equating linear velocity and angular velocity,
V = ω*r
Where,
ω Is the angular speed in rad/s
r is the radius of the circle in m
= 3 cm
= 3cm * 1m/100 cm = 0.03 m
ω = V/r
= 0.2824/0.03
= 9.412 rad/s.
Answer:
F = 176.175 N
Explanation:
given,
radius of merry - go - round = 2.7 m
mass of the disk = 800 kg
speed of the merry- go-round = 18 rpm
= 18 
= 1.88 rad/s
time = 13 s
mass of two children = 25 kg
ω = ω₀ + α t
1.88 = 0 + α(13)
α = 0.145 rad/s²
we know
τ = I α
so,
τ = I α
τ = 3280.5 x 0.145
τ = 475.67 N m
τ = F x r
475.67 = F x 2.7
F = 176.175 N