Answer: 287.8 cm3
Explanation:
Given that:
Initial volume of gas V1 = 350 cm3
Initial pressure of gas P1 = 740 mmHg
New volume V2 = ?
New pressure P2 = 900 mmHg
Since, pressure and volume are involved while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
740 mmHg x 350 cm3 = 900mmHg x V2
V2 = (740 mmHg x 350 cm3) /900mmHg
V2 = 259000 mmHg cm3 / 900mmHg
V2 = 287.8 cm3
Thus, the gas will occupy 287.8 cubic centimeters at the new pressure.
Answer:
The answer to your question is Cm = 2.093 J/kg°C
Explanation:
Data
mass metal = mass of water
Δ water = 5°
Δ metal = 10°
Cm = ?
Cw = 4.186 J/Kg°C
Formula
for metal for water
mCmΔTm = mCwΔTw
Cancel mass of metal
Cm ΔTm = CwΔTw
solve for Cm
Cm = (CwΔTw) / ΔTm
Substitution
Cm = (4.186 x 5) / 10
Simplification
Cm = 20.93 / 10
Result
Cm = 2.093 J/kg°C
12 moles H2O
Explanation:
Your tools of choice for stoichiometry problems will always be the mole ratios that exist between the chemical species that take part in the reaction.
As you know, the stoichiometric coefficients attributed to each compound in the balanced chemical equation can be thought of as moles of reactants needed or moles of products formed in the reaction.
The equilibrium state of a gas when it can hold all the molecules of water vapor is known as saturation.
<h3>Which three equilibrium conditions apply?</h3>
A solid substance subjected to three forces with divergent lines of action is in equilibrium if all three of the following three circumstances hold true:
- Coplanar action lines are present (in the same plane)
- The paths of action have come together (they cross at the same point)
- These forces add up to a vector with a total of zero.
<h3>What are equilibrium's first and second conditions?</h3>
An object must satisfy two requirements of equilibrium in order to maintain static equilibrium.
- First, there must be no net force acting on the item.
- Second, there must be no net torque pulling on the object.
learn more aboute quilibrium condition here
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