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3 years ago

7

Calculate the number of Calories present in a chocolate chip cookie that contains 19 g carbohydrate, 3 g protein, and 9 g fat.

1 answer:

agasfer [191]3 years ago

5 0

Im unsure :( maybe try looking up a calorie calculator

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What is one molar volume of the gas ammonia (NH3) at STP ?

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D 42.2 L/mol I’s is it I got it correct

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2 years ago

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What is true if a liquid and a gas are in equilibrium?

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A - Liquid molecules forming a gas and gas molecules forming a

liquid are equal in number.

Explanation:

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3 years ago

_P4 + ____O2 → __P2O3<br><br> How do I balance this equation?

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Consider the half reaction below.

Radda [10]

Answer: the second option: <span>Iron is being oxidized
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Explanation:

1) Oxidation is the increase of the oxidation state (number) due to the loss of electrons.

2) In the given reaction, you can see that in the left side the atom is Fe.

When an element (atom) is not combined (or combined with it self) its oxidation state is 0.

3) In the right side of the given equation you that iron is now in form of cation with charge 2+: Fe²⁺.

That means that the new oxidation state of the element is 2+.

4) This change in the oxidation state, of course, is accompanied by the loss of the two electrons: 2e⁻.

5) Conclusion: the iron has oxidized by losing two electrons and increasing its oxidation state from 0 to 2+.
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3 years ago

Match each transition metal ion with its condensed ground-state electron configuration. A [Ar]3d2 B [Ar]4s23d3 C [Kr]4d10 D [Xe]

madreJ [45]

Answer:

$Mn^{2+}$ : - F . $[Ar]3d^{5}$

$Hg^{2+}$ : - G. $[Xe]4f^{14}5d^{10}$

$La^{3+}$ : - D. $[Xe]$

$Fe^{3+}$ : - F. $[Ar]3d^{5}$

$Ag^{+}$ : - C. $[Kr]4d^{10}$

$Co^{3+}$ : - E. $[Ar]3d^{6}$

Explanation:

The electronic configuration of the element Mn is:-

$[Ar]3d^{5}4s^2$

For, $Mn^{2+}$ , 2 electrons are lost, thus the configuration is:-

$[Ar]3d^{5}$

The electronic configuration of the element Hg is:-

$[Xe]4f^{14}5d^{10}6s^2$

For, $Hg^{2+}$ , 2 electrons are lost, thus the configuration is:-

$[Xe]4f^{14}5d^{10}$

The electronic configuration of the element La is:-

$[Xe]5d^{1}6s^2$

For, $La^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Xe]$

The electronic configuration of the element Fe is:-

$[Ar]3d^{6}4s^2$

For, $Fe^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Ar]3d^{5}$

The electronic configuration of the element Ag is:-

$[Kr]4d^{10}5s^1$

For, $Ag^{+}$ , 1 electron is lost, thus the configuration is:-

$[Kr]4d^{10}$

The electronic configuration of the element Co is:-

$[Ar]3d^{7}4s^2$

For, $Co^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Ar]3d^{6}$

7 0

3 years ago