$(\stackrel{x_1}{3}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{16}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{16}-\stackrel{y1}{10}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{3}}} \implies \cfrac{ 6 }{ 3 } \implies 2$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{ 2}(x-\stackrel{x_1}{3}) \\\\\\ y-10=2x-6\implies {\Large \begin{array}{llll} y=2x+4 \end{array}}$

4 0

1 year ago

A candy store uses a 50% markup on cost. Find out the owners cost of a candy bar that sells for $1.50.

bulgar [2K]

Answer:

The owners' cost of the candy bar is $1

Step-by-step explanation:

Assume that the owners' cost of the candy bar is 100%

∵ The owners' cost of the candy bar is 100%

∵ The candy store uses a 50% markup on cost

∵ The selling cost = owners' cost + markup

∴ The selling cost = 100% + 50% = 150%

∵ The candy bar sells for $1.50

→ That means 1.50 is 150% of the owners' cost

∴ 1.50 = 150% × owners' cost

→ Change 150% to decimal by divide it by 100

∵ 150% = 150 ÷ 100 = 1.50

∴ 1.50 = 1.50 × owners' cost

→ Divide both sides by 1.50

∴ 1 = owners' cost

∴ The owners' costs = $1

∴ The owners' cost of the candy bar is $1

5 0

3 years ago

Which graph of a relation is not a function

Yanka [14]

Answer:

Step-by-step explanation:

Any input that has 2 or more outputs is not a function. Since D is the only graph that has two or more lines "overlapping" each other, it is not a function.

Hope this helps!

5 0

3 years ago

Read 2 more answers

saw5 [17]

Answer:

$FJ=35\ units$