1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
joja [24]
3 years ago
8

How many gold atoms are in a 1kg gold bar?

Physics
2 answers:
Naya [18.7K]3 years ago
7 0

Answer:

The answer is a 1 kilo gold bar has 32.15 ounces of gold or 1000 grams.

Explanation:

SpyIntel [72]3 years ago
3 0

Answer:

. You use the fact that 1 mole of any substance contains exactly 6.022⋅1023 atoms or molecules of that substance - this is known as Avogadro's number. In your case, 1 mole of gold will have exactly 6.022⋅1023 atoms of gold

Explanation:

Well, what is the molar mass of gold metal?

My (and your!) Periodic Table tells me that it has a molar mass of 196.97∙g∙mol−1.

And so (i) we determine the molar quantity of gold, i.e.

Moles of gold≡1000∙g196.97∙g∙mol−1≡5.077∙mol.

And (ii), since we KNOW that 1∙mol represents 6.02214076×1023 individual items…we take the product….

5.077∙mol×6.02214076×1023∙mol−1≡3.057×1024∙individual gold atoms.

Given that gold is worth $48–30 USD∙g−1 how much is this mass worth? And what is the price for an ATOM of gold?

You might be interested in
Give an example of hypothesis for an experiment and then identify its dependent and independent variables. Write all the steps o
e-lub [12.9K]
An example of a hypothesis for an experiment might be: “A basketball will bounce higher if there is more air it”

Step one would be to make an observation... “hey, my b-ball doesn’t have much air in it, and it isn’t bouncing ver high”

Step two is to form your hypothesis: “A basketball will bounce higher if there is more air it”

Step three is to test your hypothesis: maybe you want to drop the ball from a certain height, deflate it by some amount and then drop it from that same height again, and record how high the ball bounced each time.


Here the independent variable is how much air is in the basketball (what you want to change) and the dependent variable is how high the b-ball will bounce (what will change as a result of the independent variable)

Step four is to record all of your results and step five is to analyze that data. Does your data support your hypothesis? Why or why not?

You should only test one variable at a time because it is easier to tell why the results are how they are; you only have one cause.

Hope this helps!
6 0
3 years ago
Sort each item to the correct location,
Hitman42 [59]

Answer:

the orbits of the planets are elliptical

the sun is the center of the solar system

includes 9 planets

3 0
3 years ago
A student, standing on a scale in an elevator at rest, sees that his weight is 840 N. As the elevator rises, his weight increase
ololo11 [35]

As per FBD while its accelerating upwards

we can say that

F_n - mg = ma

here normal force is given as

F_n = 1050 N

W = 840 N

now mass is given as

m(9.8) = 840

m = 85.7 kg

now we will have

1050 - 840 = 85.7 \times a

a = 2.45 m/s^2

Now while accelerating downwards we can say by FBD

mg - F_n = ma

again plug in all values

840 - 588 = 85.7 \times a

a = 2.94 m/s^2

5 0
3 years ago
If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2
kaheart [24]

Answer:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

So then the difference of temperature across the material would be \Delta T = 375 K

Explanation:

For this case we can use the Fourier Law of heat conduction given by the following equation:

Q = -kA \frac{\Delta T}{\Delta x}   (1)

Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 represent the cross sectional area

Q= 3KW represent the rate of heat transfer

\Delta T is the temperature of difference that we want to find

\Delta x=2.5 cm =0.025 m represent the thickness of the material

If we solve \Delta T in absolute value from the equation (1) we got:

\Delta T =\frac{Q \Delta x}{Ak}

First we convert 3KW to W and we got:

Q= 3 KW* \frac{1000W}{1 Kw}= 3000 W

And we have everything to replace and we got:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

So then the difference of temperature across the material would be \Delta T = 375 K

5 0
3 years ago
I NEED HELP ASAP! PLSSSSSSSSSSSSSSSSSSS
OleMash [197]
I’m pretty sure

Part 1; C
Part 2; C

Not 100% sure tho :)
5 0
3 years ago
Other questions:
  • What is the speed of a 48-kilogram dog running across<br>a lawn with 216 joules of kinetic energy?​
    9·1 answer
  • You did 200 joules of work lifting a 150-newton backpack. How high did you lift the backpack?
    10·1 answer
  • A block with mass m =7.4 kg is hung from a vertical spring. when the mass hangs in equilibrium, the spring stretches x = 0.22 m.
    8·1 answer
  • A tiger leaps with an initial velocity of 35.0 km/hr at an angle of 13.0ᶿ with respect to the horizontal. What are the component
    13·1 answer
  • If two automobiles have the same velocity do they have the same acceleration?
    10·2 answers
  • What’s the answer?hhhu
    8·1 answer
  • An 85 kg man and his 35 kg daughter are sitting on opposite ends of a 3.00 m see-saw. The see-saw is anchored in the center. If
    15·1 answer
  • Please help!
    7·2 answers
  • 5. What is the amount of force required to accelerate a 20 kg object at a rate of 5 m/sz?
    6·1 answer
  • All ball is thrown up with a vertical velocity of 54 m/s and a horizontal velocity of 39 m/s. Calculate how many seconds it will
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!