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VARVARA [1.3K]
2 years ago
12

What would a drummer do to make the sound of a drum give a note of lower pitch?

Physics
1 answer:
SashulF [63]2 years ago
4 0
The best and most correct answer among the choices provided by your question is the third choice or letter C.

Hitting the drum skin nearer the edge is what <span>would a drummer do to make the sound of a drum give a note of lower pitch.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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resolve the position vector A of thd car (measured from fixed point O) into components parallel to OB and OC
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3 years ago
What is the momentum of a child and a bicycle if the total mass of th
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6 0
2 years ago
How to calculate moments with 3 separate weights of different amounts at different points?
Rina8888 [55]
I don't completely understand your drawing, although I can see that you certainly
did put a lot of effort into making it.  But calculating the moment is easy, and we
can get along without the drawing.

Each separate weight has a 'moment'.
The moment of each weight is: 

             (the weight of it) x (its distance from the pivot/fulcrum) .

That's all there is to a 'moment'.

The lever (or the see-saw) is balanced when (the sum of all the moments
on one side) is equal to (the sum of the moments on the other side).

That's why when you're on the see-saw with a little kid, the little kid has to sit
farther away from the pivot than you do.  The kid has less weight than you do,
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6 0
3 years ago
Which parts of Dalton’s atomic theory had to be revised
eduard
<span> The indivisibility of an atom was proved wrong an atom can be further subdivided into protons, neutrons and electrons. However an atom is the smallest particle that takes </span>part<span> in chemical reactions</span>
7 0
3 years ago
The resistivity of gold is at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a current of 940 m
IgorC [24]

Answer:

0.0360531138247 V/m

Explanation:

\rho = Resistivity of gold = 2.44\times 10^{-8}\ \Omega .m (General value)

I = Current = 940 mA

d = Diameter = 0.9 mm

A = Area = \dfrac{\pi}{4}d^2

E = Electric field

Resistivity is given by

\rho=\dfrac{EA}{I}\\\Rightarrow E=\dfrac{\rho I}{A}\\\Rightarrow E=\dfrac{2.44\times 10^{-8}\times 940\times 10^{-3}}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}\\\Rightarrow E=0.0360531138247\ V/m

The  electric field in the wire is 0.0360531138247 V/m

6 0
3 years ago
Read 2 more answers
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