The launch speed of a horizontally launched projectile is 13.28 m/s.
<h3>
Time of motion of the projectile</h3>
The time of motion is calculated as follows;
t = √(2h / g)
where;
- h is height of the cliff
- g is acceleration due to gravity
t = √(2 x 19.3 / 9.8)
t = 1.98 s
<h3>Launch speed of the projectile</h3>
X = Vxt
Vx = X/t
Vx = (26.3)/(1.98)
Vx = 13.28 m/s
Thus, the launch speed of a horizontally launched projectile is 13.28 m/s.
Learn more about horizontal speed here: brainly.com/question/24949996
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So the answer is 324.
Explanation
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Answer: The correct answer is option (C).
Explanation:
As it is given in the problem, the path of a meteor passing Earth is affected by its gravitational force and falls to Earth's surface. Another meteor of the same mass falls to Jupiter's surface due to its gravitational force.
According to Newton's law of universal gravitational, every particle attracts every other particles in the universe with the gravitational force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The Jupiter is the most massive planet in the solar system. It is also the largest planet in the solar system. The gravity of Jupiter on its surface is 2.4 times that of surface gravity of the Earth.
If a person weighs 100 pounds on the Earth then he would weigh 240 pounds on Jupiter.
Therefore, the correct answer is option (C), the meteor falls to Jupiter faster due to its greater gravitational force.
As electrons move through the conductor, some collide with atoms, other electrons, or impurities in the metal.
