Answer:
The availability of system will be 0.9
Explanation:
We have given mean time of failure = 900 hours
Mean time [to repair = 100 hour
We have to find availability of system
Availability of system is given by 
So availability of system 
So the availability of system will be 0.9
Answer:
The annual operating cost of the refrigerator is $102.78.
Explanation:
Power consumed by the refrigerator = 247 W = 247/1000 = 0.247 kW
Daily operation of the refrigerator = 19 hours
Annual operation of the refrigerator = 365 × 19 = 6,935 hours
Annual energy consumed = 0.247 kW × 6,935 hours = 1712.945 kWh
1 kWh of electricity cost $0.06
1712.945 kWh will cost 1712.945 × $0.06 = $102.78
Annual operating cost = $102.78
Answer:
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answer : NOR1(q_) wave is complementary to NOR2(q)
Explanation:
Note ; NOR 2 will be addressed as q in the course of this solution while NOR 1 will be addressed as q_
Initial state is unknown i.e q = 0 and q_= 1
from the diagram the waveform reset and set
= from 0ns to 20ns reset=1 and set=0.from the truth table considering this given condition q=0 and q_bar=1 while
from 30ns to 50ns reset=0 and set=1.from the truth table considering this condition q=1 and q_bar=1.so from 35ns also note there is a delay of 5 ns for the NOR gate hence the NOR 2 will be higher ( 1 )
From 50ns to 65ns both set and reset is 0.so NOR2(q)=0.
From 65 to 75 set=1 and reset=0,so our NOR 2(q)=1 checking from the truth table
also from 75 to 90 set=1 and reset=1 , NOR2(q) is undefined "?" and is mentioned up to 95ns.
since q_ is a complement of q, then NOR1(q_) wave is complementary to NOR2(q)
the function is to provide sealed combustion so that the loss of gas is minimized
Answer:
q=2313.04
T=690.86°C
Explanation:
Given that
Thickness t= 20 cm
Thermal conductivity of firebrick= 1.6 W/m.K
Thermal conductivity of structural brick= 0.7 W/m.K
Inner temperature of firebrick=980°C
Outer temperature of structural brick =30°C
We know that thermal resistance

These are connect in series

Heat transfer

So heat flux
q=2313.04
Lets temperature between interface is T
Now by equating heat in both bricks

So T=690.86°C