Answer:
Airplanes' wings are curved on top and flatter on the bottom. That shape makes air flow over the top faster than under the bottom. As a result, less air pressure is on top of the wing. This lower pressure makes the wing, and the airplane it's attached to, move up.
Explanation:
Answer:
the difference in pressure between the inside and outside of the droplets is 538 Pa
Explanation:
given data
temperature = 68 °F
average diameter = 200 µm
to find out
what is the difference in pressure between the inside and outside of the droplets
solution
we know here surface tension of carbon tetra chloride at 68 °F is get from table 1.6 physical properties of liquid that is
σ = 2.69 ×
N/m
so average radius =
= 100 µm = 100 ×
m
now here we know relation between pressure difference and surface tension
so we can derive difference pressure as
2π×σ×r = Δp×π×r² .....................1
here r is radius and Δp pressure difference and σ surface tension
Δp =
put here value
Δp =
Δp = 538
so the difference in pressure between the inside and outside of the droplets is 538 Pa
Answer:
Taking as a basis of calculation 100 mol of gas leaving the conversion reactor, draw andcompletely label a flowchart of this process. Then calculate the moles of fresh methanol feed,formaldehyde product solution, recycled methanol, and absorber off-gas, the kg of steamgenerated in the waste-heat boiler, and the kg of cooling water fed to the heat exchangerbetween the waste-heat boiler and the absorber. Finally, calculate the heat (kJ) that must beremoved in the distillation column overhead condenser, assuming that methanol enters as asaturated vapor at 1 atm and leaves as a saturated liquid at the same pressure.
1
SEE ANSWER
Explanation:
Answer:
The strength coefficient is K = 591.87 MPa
Explanation:
We can calculate the strength coefficient using the equation that relates the tensile strength with the strain hardening index given by
![S_{ut}=K \left(\cfrac ne \right)^n](https://tex.z-dn.net/?f=S_%7But%7D%3DK%20%5Cleft%28%5Ccfrac%20ne%20%5Cright%29%5En)
where Sut is the tensile strength, K is the strength coefficient we need to find and n is the strain hardening index.
Solving for strength coefficient
From the strain hardening equation we can solve for K
![K = \cfrac{S_{ut}}{\left(\cfrac ne \right)^n}](https://tex.z-dn.net/?f=K%20%3D%20%5Ccfrac%7BS_%7But%7D%7D%7B%5Cleft%28%5Ccfrac%20ne%20%5Cright%29%5En%7D)
And we can replace values
![K = \cfrac{275}{\left(\cfrac {0.4}e \right)^{0.4}}\\K=591.87](https://tex.z-dn.net/?f=K%20%3D%20%5Ccfrac%7B275%7D%7B%5Cleft%28%5Ccfrac%20%7B0.4%7De%20%5Cright%29%5E%7B0.4%7D%7D%5C%5CK%3D591.87)
Thus we get that the strength coefficient is K = 591.87 MPa
Answer: I think The left-hand panel shows like a high level list of folders. And Right-hand panel shows the contents of selected folder.