Answer:2.53°
Explanation:The ball is undergoing a projectile motion that is why it has an angle
Range = (U^2 sin2a)/g
U= velocity of the ball=100ft/sec
Range of the ball(i.e horizontal distance the ball crossed)= 30yard=90ft
a=angle the ball is projected
g= acceleration due to gravity=9.8m/s^2
90=(100^2×sin2a)/9.8
90×9.8=10000×sin2a
882/10000=sin2a
0.0882=sin2a
Sin^-1 0.0882=2a
5.06=2a
a=5.06/2
a=2.53
Answer:
Explanation:
t1 = 1000 F = 1460 R
t0 = 80 F = 540 R
T2 = 3600 R
The working substance has an available energy in reference to the 80F source of:
B1 = Q1 * (1 - T0 / T1)
B1 = 100 * (1 - 540 / 1460) = 63 BTU
The available energy of the heat from the heat wource at 3600 R is
B2 = Q1 * (1 - T0 / T2)
B2 = 100 * (1 - 540 / 3600) = 85 BTU
The reduction of available energy between the source and the 1460 R temperature is:
B3 = B2 - B1 = 85 - 63 = 22 BTU
Answer:
Explanation:
Given
velocity at A is 
For 
velocity is increasing at 
Tangential acceleration is given by





at 


thus 
Velocity in terms of Displacement is given by



When car has traveled
th of distance i.e.




on solving we get 
Thus velocity at 

(b)Acceleration when car has traveled three-fourth the way of track
normal acceleration 

Tangential acceleration 

Net acceleration 
