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Westkost [7]
3 years ago
15

Who does each person work for? Monica works for a power company, Travis works for a utilities company, and Maggie is self-employ

ed. All three people work for a power company. All three people are self-employed. Monica works for a utilities company, Travis is self-employed, and Maggie works for a power company.
Engineering
2 answers:
maksim [4K]3 years ago
8 0

Answer:

A per the chart given, it can be clearly said

Monica works for a utilities company, Travis is self-employed, and Maggie works for a power company.

Explanation:

Monica probably works for a utilities company since she is responsible for checking gas meters on houses, while Travis is more likely to be self-employed since he installs solar panels on houses – though he can be employed by a company which sells solar company installation services, but the option is available. Since Maggie works on power lines, she is most definitely employed by a power company.

Paraphin [41]3 years ago
4 0

Answer:

The correct answer is D!

Explanation:

youre welcommee!

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A driver takes 3.5 s to react to a complex situation while traveling at a speed of 60 mi/h. How far does the vehicle travel befo
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Answer:

x = 93.8 m.

Explanation:

During the entire the reaction time interval, the vehicle continues moving at the same speed that it was moving, i.e., 60 mi/hr.

In order to calculate the distance in meters, travelled at that speed, it is advisable first to convert the 60 mi/hr to m/seg, as follows:

60 mi/hr = 60*\frac{1hr}{3,600s}*\frac{1,605m}{1mi} = 26.8 m/s

Applying the definition of average velocity, we can solve for Δx, as follows:

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7 0
3 years ago
Systematic searching is a skill that takes ________ to master.
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A westbound section of freeway currently has three 12-ft wide lanes, a 6-ft right shoulder, and no ramps within 3 miles upstream
Tresset [83]

Answer:

•Estimated density = 39.685Pc/mi/en

•Level of service, LOS frequency = LOSC

Explanation:

We are given:

•Freeway current lane width,B = 12ft

• freeway current shoulder width,b = 6ft

• percentage of heavy vehicle, Ptb = 10℅

• peak hour factor, PHF = 0.9

Let's consider,

•Number of lanes N = 4

• flow of traffic V = 7500vph

• percentage of Rv = 0, therefore the freeflow speed in freeway FFS = 70mph

• cars equivalent for recreational purpose Er= 2

•cars to be used for trucks and busses Etb= 2.5

Let's first calculate for the heavy adjustment factor.

We have:

F_H_v = \frac{1}{1+P_t_b(E_t_b-1)+Pr(Er-1)}

Substituting figures in the equation we have:

= \frac{1}{1+0.1(2.5-1)+0(2-1)}

= 0.75

Let's now calculate equivalent flow rate of the car using:

Vp = \frac{V}{(P_H_F)*N)*(F_H_v)*(F_p)}

= \frac{7500}{0.9*4*0.75*1}

= 2777.7 pc/h/en

Calculating for traffic density, we have:

D = \frac{Vp}{FFS}

D = \frac{2777.7}{70}

D = 39.685 Pc/mi/en

Using the table for LOS criteria of basic frequency segment, the level of service LOS of frequency is LOSC

4 0
3 years ago
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