Answer: A fly wheel having a mass of 30kg was allowed to swing as pendulum about a knife edge at inner side of the rim as shown in figure.
Explanation:
Answer:
The availability of system will be 0.9
Explanation:
We have given mean time of failure = 900 hours
Mean time [to repair = 100 hour
We have to find availability of system
Availability of system is given by ![\frac{mean\time\ of\ failure}{mean\ time\ of\ failure+mean\ time\ to\ repair}](https://tex.z-dn.net/?f=%5Cfrac%7Bmean%5Ctime%5C%20of%5C%20failure%7D%7Bmean%5C%20time%5C%20of%5C%20failure%2Bmean%5C%20time%5C%20to%5C%20repair%7D)
So availability of system ![=\frac{900}{900+100}=\frac{900}{1000}=0.9](https://tex.z-dn.net/?f=%3D%5Cfrac%7B900%7D%7B900%2B100%7D%3D%5Cfrac%7B900%7D%7B1000%7D%3D0.9)
So the availability of system will be 0.9
Answer:
We can compute the diameter of the tree T by a pruning procedure, starting at the leaves (external nodes).
- Remove all leaves of T. Let the remaining tree be T1.
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Remove all leaves of T1. Let the remaining tree be T2.
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Repeat the "remove" operation as follows: Remove all leaves of Ti. Let remaining tree be Ti+1.
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When the remaining tree has only one node or two nodes, stop! Suppose now the remaining tree is Tk.
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If Tk has only one node, that is the center of T. The diameter of T is 2k.
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If Tk has two nodes, either can be the center of T. The diameter of T is 2k+1.
Explanation:
We can compute the diameter of the tree T by a pruning procedure, starting at the leaves (external nodes).
- Remove all leaves of T. Let the remaining tree be T1.
-
Remove all leaves of T1. Let the remaining tree be T2.
-
Repeat the "remove" operation as follows: Remove all leaves of Ti. Let remaining tree be Ti+1.
-
When the remaining tree has only one node or two nodes, stop! Suppose now the remaining tree is Tk.
-
If Tk has only one node, that is the center of T. The diameter of T is 2k.
-
If Tk has two nodes, either can be the center of T. The diameter of T is 2k+1.
Answer:
A force must s applied to a wall or roof rafters to add strength and keep the building straight and plumb
Given Information:
Initial temperature of aluminum block = 26.5°C
Heat flux = 4000 w/m²
Time = 2112 seconds
Time = 30 minutes = 30*60 = 1800 seconds
Required Information:
Rise in surface temperature = ?
Answer:
Rise in surface temperature = 8.6 °C after 2112 seconds
Rise in surface temperature = 8 °C after 30 minutes
Explanation:
The surface temperature of the aluminum block is given by
![T_{surface} = T_{initial} + \frac{q}{k} \sqrt{\frac{4\alpha t}{\pi} }](https://tex.z-dn.net/?f=T_%7Bsurface%7D%20%3D%20T_%7Binitial%7D%20%2B%20%5Cfrac%7Bq%7D%7Bk%7D%20%5Csqrt%7B%5Cfrac%7B4%5Calpha%20t%7D%7B%5Cpi%7D%20%7D)
Where q is the heat flux supplied to aluminum block, k is the conductivity of pure aluminum and α is the diffusivity of pure aluminum.
After t = 2112 sec:
![T_{surface} = 26.5 + \frac{4000}{237} \sqrt{\frac{4(9.71\times 10^{-5}) (2112)}{\pi} }\\\\T_{surface} = 26.5 + \frac{4000}{237} (0.51098)\\\\T_{surface} = 26.5 + 8.6\\\\T_{surface} = 35.1\\\\](https://tex.z-dn.net/?f=T_%7Bsurface%7D%20%3D%2026.5%20%2B%20%5Cfrac%7B4000%7D%7B237%7D%20%5Csqrt%7B%5Cfrac%7B4%289.71%5Ctimes%2010%5E%7B-5%7D%29%20%282112%29%7D%7B%5Cpi%7D%20%7D%5C%5C%5C%5CT_%7Bsurface%7D%20%3D%2026.5%20%2B%20%5Cfrac%7B4000%7D%7B237%7D%20%280.51098%29%5C%5C%5C%5CT_%7Bsurface%7D%20%3D%2026.5%20%2B%208.6%5C%5C%5C%5CT_%7Bsurface%7D%20%3D%2035.1%5C%5C%5C%5C)
The rise in the surface temperature is
Rise = 35.1 - 26.5 = 8.6 °C
Therefore, the surface temperature of the block will rise by 8.6 °C after 2112 seconds.
After t = 30 mins:
![T_{surface} = 26.5 + \frac{4000}{237} \sqrt{\frac{4(9.71\times 10^{-5}) (1800)}{\pi} }\\\\T_{surface} = 26.5 + \frac{4000}{237} (0.4717)\\\\T_{surface} = 26.5 + 7.96\\\\T_{surface} = 34.5\\\\](https://tex.z-dn.net/?f=T_%7Bsurface%7D%20%3D%2026.5%20%2B%20%5Cfrac%7B4000%7D%7B237%7D%20%5Csqrt%7B%5Cfrac%7B4%289.71%5Ctimes%2010%5E%7B-5%7D%29%20%281800%29%7D%7B%5Cpi%7D%20%7D%5C%5C%5C%5CT_%7Bsurface%7D%20%3D%2026.5%20%2B%20%5Cfrac%7B4000%7D%7B237%7D%20%280.4717%29%5C%5C%5C%5CT_%7Bsurface%7D%20%3D%2026.5%20%2B%207.96%5C%5C%5C%5CT_%7Bsurface%7D%20%3D%2034.5%5C%5C%5C%5C)
The rise in the surface temperature is
Rise = 34.5 - 26.5 = 8 °C
Therefore, the surface temperature of the block will rise by 8 °C after 30 minutes.