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spin [16.1K]
3 years ago
14

Which is not an affect of alcohol

Engineering
1 answer:
Gre4nikov [31]3 years ago
6 0
Pooping problems is not an affect
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What is an obstacle that holds people back from getting their car fixed?
docker41 [41]

Answer:

Not having enough money to pay to get it fixed

Explanation:

6 0
3 years ago
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Air enters an adiabatic gas turbine at 1590 oF, 40 psia and leaves at 15 psia. The turbine efficiency is 80%, and the mass flow
melamori03 [73]

Answer:

a) 158.4 HP.

b) 1235.6 °F.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up an energy balance for the turbine's inlets and outlets:

m_{in}h_{in}=W_{out}+m_{out}h_{out}

Whereas the mass flow is just the same, which means we have:

W_{out}=m_{out}(h_{out}-h_{in})

And the enthalpy and entropy of the inlet stream is obtained from steam tables:

h_{in}=1860.7BTU/lbm\\\\s_{in}= 2.2096BTU/lbm-R

Now, since we assume the 80% accounts for the isentropic efficiency for this adiabatic gas turbine, we assume the entropy is constant so that:

s_{out}= 2.2096BTU/lbm-R

Which means we can find the temperature at which this entropy is exhibited at 15 psia, which gives values of temperature of 1200 °F (s=2.1986 BTU/lbm-K) and 1400 °F (s=2.2604 BTU/lbm-K), and thus, we interpolate for s=2.2096 to obtain a temperature of 1235.6 °F.

Moreover, the enthalpy at the turbine's outlet can be also interpolated by knowing that at 1200 °F h=1639.8 BTU/lbm and at 1400 °F h=174.5 BTU/lbm, to obtain:

h_{out}=1659.15BUT/lbm

Then, the isentropic work (negative due to convention) is:

W_{out}=2500lbm/h(1659.15BUT/lbm-1860.7BUT/lbm)\\\\W_{out}=-503,875BTU

And the real produced work is:

W_{real}=0.8*-503875BTU\\\\W_{real}=-403100BTU

Finally, in horsepower:

W_{real}=-403100BTU/hr*\frac{1HP}{2544.4336BTU/hr} \\\\W_{real}=158.4HP

Regards!

6 0
3 years ago
The acrylic plastic rod is 200 mm long and 15 mm in diameter. If an axial load of 300 N is applied to it, determine the change i
ehidna [41]

Answer:

Change in length = 0.1257 mm

Change in diameter= -0.03771mm

Explanation:

Given

Diameter, d = 15 mm

Length of rod, L = 200mm

F = Force= 300N

d = 0.015m

Ep=2.70 GPa, np=0.4.

First, we have to calculate the normal stress using

σ = F/A where F = Force acting on the Cross-sectional area

A = Area

Area is calculated as πd²/4 where d = 0.015m

A = 22/7 * 0.015²/4

A = 0.000176785714285m²

A = 1.768E-4m²

So, stress. σ = 300N/1.768E-4m²

σ = 1696832.579185520Pa

σ = 1.697MPa

Calculating E(long)

E(long) = σ /Ep

E(long) = 1.697E-3/2.70

E(long) = 0.0006285

At this point, we fan now calculate the change in length of the element;

∆L = E(long) * L

∆L = 0.0006285 * 200mm

∆L = 0.1257mm

Calculating E(lat)

E(lat) = -np * E(long)

E(lat) = -4 * 0.0006285

E(lat) = -0.002514

At this point, we can now calculate the change in diameter of the element;

∆D = E(lat) * D

∆L = -0.002514 * 15mm

∆L = -0.03771mm

8 0
3 years ago
Are commonly made out of cast iron and connect directly to the engine
iren [92.7K]

Answer:

The engine block.

Explanation:

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Which of the following is true regarding screw gauges and shank?
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correct me if i’m wrong i’m pretty sure it’s B i’ve had the same question
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