Answer:
6,216.684 kilograms of sodium carbonate must be added to neutralize of sulfuric acid solution.
Explanation:
Mass of sulfuric acid solution =
Percentage mass of sulfuric acid = 95.0%
Mass of sulfuric acid =
Moles of sulfuric acid =
According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.
Then 58,647.96 moles of sulfuric acisd will be neutralized by :
of sodium carbonate
Mass of 58,647.96 moles of sodium carbonate :
6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg
6,216.684 kilograms of sodium carbonate must be added to neutralize of sulfuric acid solution.
Answer: A plot of the natural log of the concentration of the reactant as a function of time is linear.
Explanation:
Since it was explicitly stated in the question that the half life is independent of the initial concentration of the reactant then the third option must necessarily be false. Also, the plot of the natural logarithm of the concentration of reactant against time for a first order reaction is linear. In a first order reaction, the half life is independent of the initial concentration of the reactant. Hence the answer.
The final answer is 2.25 atm
If you want full steps tell me
Answer:
Explanation:
1. Convert millilitres to litres
2. Calculate the concentration
Answer:
75 N
Explanation:
i just know bc i did this question like 10 minitues ago im postive im right