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Dmitry_Shevchenko [17]
2 years ago
8

A classroom has 24 fluorescent bulbs, each of which is 32 W. how much energy does it take to light the room for a minute?(unit=J

)PLEASE HELP
Physics
2 answers:
cestrela7 [59]2 years ago
3 0

Answer:

Energy= 46.08KJ

Explanation:

Given that the power needed to light each bulb is 32W

We know that Power = \frac{energy}{time}

The energy needed to light one bulb=power*time

Given time = 1minute = 60 seconds

Energy = 32W*60sec=1920J

Therefore energy needed to light one bulb is 1920J

The energy needed to light 24 bulbs = 1920*24 =46080J=46.08KJ

Alborosie2 years ago
3 0
<h2>46.08kJ</h2>

Explanation:

        There are a total of 24 bulbs in the room, each of which has a rated wattage of 32 W.

        We need to light the room for a minute. Total power demanded by bulbs=(\textrm{Number of bulbs})\times(\textrm{Wattage of each bulb})\textrm{ = }24\times32W\textrm{ = }768W.

        We now know the demanded power. Power is energy required per unit time.

Power\textrm{ = }\frac{Energy}{time}

Energy\textrm{ = }Power\times time \textrm{ = }768\textrm{ }W\times1\textrm{ }min\textrm{ = }768\textrm{ }\frac{J}{sec}\times 60\textrm{ }sec\textrm{ = }46,080J

∴ Energy required = 46,080J=46.08kJ

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g The potential energy of a pair of hydrogen atoms separated by a large distance x is given by U(x)=−C6/x6, where C6 is a positi
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Data provided in the question

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Force exerted by one atom upon another

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or

F_x = \frac{\partial}{\partial X}  (\frac{C_6}{X^6})

or

F_x = -\frac{6 C_6}{2^7}

As we can see that the C_6 comes in positive and constant which represents that the force is negative that means the force is attractive in nature

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vladimir1956 [14]

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Answer:

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