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Dmitry_Shevchenko [17]
3 years ago
8

A classroom has 24 fluorescent bulbs, each of which is 32 W. how much energy does it take to light the room for a minute?(unit=J

)PLEASE HELP
Physics
2 answers:
cestrela7 [59]3 years ago
3 0

Answer:

Energy= 46.08KJ

Explanation:

Given that the power needed to light each bulb is 32W

We know that Power = \frac{energy}{time}

The energy needed to light one bulb=power*time

Given time = 1minute = 60 seconds

Energy = 32W*60sec=1920J

Therefore energy needed to light one bulb is 1920J

The energy needed to light 24 bulbs = 1920*24 =46080J=46.08KJ

Alborosie3 years ago
3 0
<h2>46.08kJ</h2>

Explanation:

        There are a total of 24 bulbs in the room, each of which has a rated wattage of 32 W.

        We need to light the room for a minute. Total power demanded by bulbs=(\textrm{Number of bulbs})\times(\textrm{Wattage of each bulb})\textrm{ = }24\times32W\textrm{ = }768W.

        We now know the demanded power. Power is energy required per unit time.

Power\textrm{ = }\frac{Energy}{time}

Energy\textrm{ = }Power\times time \textrm{ = }768\textrm{ }W\times1\textrm{ }min\textrm{ = }768\textrm{ }\frac{J}{sec}\times 60\textrm{ }sec\textrm{ = }46,080J

∴ Energy required = 46,080J=46.08kJ

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Air escaping out from an air hose at a gas station always feels cool. Why? ​
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The diagram shows monochromatic light passing through two openings.
rusak2 [61]

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A 100 kg box as showsn above is being pulled along the x axis by a student. the box slides across a rough surface, and its posit
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Answer:

a) 2 m/s

b) i) K.E = 50 (1.5t^2 + 2) ^2\\

ii) F = 3tm

Explanation:

The function for distance is x = 0.5t ^3 + 2t

We know that:

Velocity = v= \frac{d}{dt} x

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To find the function for Kinetic Energy of the box at any time, t.

Kinetic \ Energy = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times 100 \times (1.5t^2 + 2) ^2\\\\K.E = 50 (1.5t^2 + 2) ^2\\

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a = v'(t) = 1.5t^2 + 2\\a = 3t

F = m \times a\\F= m \times 3t\\F = 3tm

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