Answer:
The pressure after passing the valve is 23,8 [Kpa] ( 0,234 atm) and the pressure drop is about 1,53 [Kpa]
Explanation:
We need to use the formula of bernoulli, in the attached image we can see the fluid throw the pipe, we also can calculate the velocity inside the pipe using the flow rate and the cross sectional area.
For this case, we don't use the elevation difference and therefore those terms can be cancelled.
When the area has reduced the velocity of the fluid is increased but there is a drop pressure through the valve.
The absolute refractive index is equal to the speed of light of the wave in air divided by the speed of light in the second medium. This means that it is equal to 3 x10^8 / 1.71 x10^8. This means the answer is 1.75
The concept that we need here to give a proper solution is mutual inductance.
The mutual inductance is given by the expression
Where,
I = current
N = Number of turns
Flux through the solenoid.
Part A) Then we have in our values that,
Replacing in the equation,
Part B) Here is required the Flux, then using the same expression we have that
We conserve the same value for the Inductance but now we have a current of 2.6, then
Therefore the flux in Solenoid 1 is 
It is due to the excess stress.
