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IRINA_888 [86]
2 years ago
10

Air escaping out from an air hose at a gas station always feels cool. Why? ​

Physics
1 answer:
kati45 [8]2 years ago
8 0

Answer:

The air is contained at a high pressure in the tube. When it escapes from a small orifice, it suddenly expands. A large amount of its heat is absorbed in the process of expansion resulting in considerable fall in its temperature. This is why the escaping air feels cold.

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How do atoms become ions explain which characteristics change in which stay the same during this transformation
Scilla [17]
Ions are charged atoms
7 0
3 years ago
A 12-kg projectile is launched with an initial vertical speed of 20 m/s. It rises to a maximum height of 18 m above the launch p
kirill115 [55]

Answer:

Change in mechanical energy, \Delta E=283.2\ J

Explanation:

It is given that,

Mass of the projectile, m = 12 kg

Speed of the projectile, v = 20 m/s

Maximum height, h = 18 m

Initially, the projectile have only kinetic energy. it is given by :

K=\dfrac{1}{2}mv^2

K=\dfrac{1}{2}\times 12\ kg\times (20\ m/s)^2

K = 2400 J

Finally, it have only potential energy. it is given by :

P = mgh

P=12\ kg\times 9.8\ m/s^2\times 18\ m

P =2116.8 J

The change in mechanical energy is given by :

\Delta E=K-P

\Delta E=2400-2116.8

\Delta E=283.2\ J

So, the change in mechanical energy is 283.2 J. Hence, this is the required solution.

8 0
3 years ago
Select the decimal that is equivalent to 29/37​
morpeh [17]

Answer:

0.78

Explanation:

6 0
3 years ago
Define friction State the law of frictionGive two factors that may affect friction
umka21 [38]

Friction:

Friction is the resistive force that acts on the body in a direction opposite to the direction of motion of the same object.

Laws of friction:

1. The frictional force acting on the object is proportional to the normal force acting on the object.

For example, if the object of mass m is moving along the horizontal surface, the normal force acting on the object is mg.

Thus, the frictional force acting on the object is,

\begin{gathered} F_r\propto F_N \\ F_r=\mu F_N \end{gathered}

where F_N is the normal force acting on the object,

\mu\text{ is the coefficient of friction}

The diagrammatic representation of the frictional force acting on the object is,

2. The frictional force acting on the object depends upon the nature of the surface in contact with the object.

3. The frictional force does not depend upon the area of contact of an object with the surface.

4. The kinetic friction acting on the object is independent of the velocity of the object.

5. The coefficient of static friction is more than the coefficient of kinetic friction.

Two factors on which the frictional force depends are:

1. The frictional force depends on the adhesion between the two bodies in contact.

2. The frictional force acting on the depends upon the roughness of the surface on which the object is moving.

3 0
1 year ago
On Earth, a spring stretches by 5.0 cm when a mass of 3.0 kg is suspended from one end.
Neko [114]

Answer:

Mass = 18.0 kg

Explanation:

From Hooke's law,

F = ke

where: F is the force, k is the spring constant and e is the extension.

But, F = mg

So that,

mg = ke

On the Earth, let the gravitational force be 10 m/s^{2}.

3.0 x 10 = k x 5.0

30 = 5k

⇒ k = \frac{30}{5} ................ 1

On the Moon, the gravitational force is \frac{1}{6} of that on the Earth.

m x \frac{10}{6} = k x 5.0

\frac{10m}{6} = 5k

⇒ k = \frac{10m}{30} ............. 2

Equating 1 and 2, we have;

\frac{30}{5}  = \frac{10m}{30}

m = \frac{900}{50}

    = 18.0

m = 18.0 kg

The mass required to produce the same extension on the Moon is 18 kg.

8 0
3 years ago
Read 2 more answers
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