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NNADVOKAT [17]
3 years ago
11

Select the correct answer. A credit union is a business that is owned by people who have something in common, offers you a place

to keep your money, and uses your funds to make more money. A. True B. False
Physics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

Answer:

The primary purpose in furthering their goal of service is to encourage members to save money. Another purpose is to offer loans to members. In fact, credit unions have traditionally made loans to people of ordinary means. YOU ARE PART OWNER. Credit unions are owned and controlled by the people, or members, who use their services. Your vote counts. A volunteer board of directors is elected by members to manage a credit union.

A credit union is a nonprofit financial cooperative owned by and operated for the benefit of its members. It accepts deposits, makes loans, and provides other services.

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square root A 1400 kg car is coasting on a horizontal road with a speed of 18 m/s . After passing over an unpaved, sandy stretch
Lina20 [59]

Answer:

The net force on the car is 2560 N.

Explanation:

According to work energy theorem, the amount of work done is equal to the change of kinetic energy by an object. If 'W' be the work done on an object to change its kinetic energy from an initial value 'K_{i}' to the final value 'K_{f}', then mathematically,

W = K_{f} - K_{i} = \dfrac{1}{2}~m~(v_{f}^{2} - v_{i}^{2})........................................(I)

where 'm' is the mass of the object and 'v_{i}' and 'v_{f}' be the initial and final velocity of the object respectively. If 'F_{net}' be the net force applied on the car, as per given problem, and 's' is the displacement occurs then we can write,

W = F_{net}~.~s.......................................................(II)

Given, m = 1400~Kg,~v_{i} = 18~m~s^{-1}~v_{f} = 14~m~s^{-1}~and~s = 35~m.

Equating equations (I) and (II),

&& - F_{net} \times 35~m = \dfrac{1}{2} \times 1400~Kg~\times(14^{2} - 18^{2})~m^{2}~s^{-2}\\&or,& F_{net} = \dfrac{\dfrac{1}{2} \times 1400~Kg~\times(14^{2} - 18^{2})}{35}~N\\&or,& F_{net} = 2560~N

6 0
3 years ago
When atoms get more and more energy, they can ionize. What can happen to a gas as more energy is added to its atoms?
Ulleksa [173]

Answer: Option (A) is the correct answer.

Explanation:

When more and more energy is provided to a gas then its atoms move more rapidly.

This rapid and continuous movement converts the gas into hot ionized ions which have positively charged ions and negatively charged electrons.

Therefore, we can conclude that as the atoms move faster, the gas can change into a plasma.

5 0
3 years ago
Read 2 more answers
What two factors determine gravitational potential energy?
Mashcka [7]
Mass & Height above the ground
7 0
4 years ago
Read 2 more answers
Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S an
insens350 [35]

Answer : The correct option is, (d) 4 times

Solution :

According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.

Formula used :

F=k_e\frac{q_1q_2}{r^2}

where,

F = electrostatic force of attraction or repulsion

k_e = Coulomb's constant

q_1 and q_2 are the charges

r = distance between two charges

First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'

F_{sq}=k_e\frac{qq}{1^2}=k_e\times q^2       ..........(1)

Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.

F_{sp}=k_e\frac{qq}{2^2}=k_e\frac{q^2}{4}     ...........(2)

Equation equation 1 and 2, we get

\frac{F_{sq}}{F_{sp}}=\frac{1}{4}

F_{sq}=4\times F_{sp}

Therefore, the force exerted between S and q is 4 times the force exerted between S and p.

5 0
3 years ago
Read 2 more answers
To practice Problem-Solving Strategy 15.1 Mechanical Waves. Waves on a string are described by the following general equation y(
NeX [460]

Answer:

The transverse displacement is   y(1.51 , 0.150) = 0.055 m    

Explanation:

 From the question we are told that

     The generally equation for the mechanical wave is

                    y(x,t) = Acos (kx -wt)

     The speed of the transverse wave is v = 8.25 \ m/s

     The amplitude of the transverse wave is A = 5.50 *10^{-2} m

     The wavelength of the transverse wave is \lambda = 0540 m

      At t= 0.150s , x = 1.51 m

 The angular frequency of the wave is mathematically represented as

          w = vk

Substituting values  

         w = 8.25 * 11.64

        w = 96.03 \ rad/s

The propagation constant k is mathematically represented as

                  k = \frac{2 \pi}{\lambda}

Substituting values

                  k = \frac{2 * 3.142}{0. 540}

                   k =11.64 m^{-1}

Substituting values into the equation for mechanical waves

      y(1.51 , 0.150) = (5.50*10^{-2} ) cos ((11.64 * 1.151 ) - (96.03  * 0.150))

       y(1.51 , 0.150) = 0.055 m    

4 0
4 years ago
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