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zhenek [66]
3 years ago
9

Three teachers burned calories dancing.

Mathematics
1 answer:
Georgia [21]3 years ago
5 0

Answer:

Mr doyle the fastest and Mr hennessy was the slowest

Step-by-step explanation:

3/4 of an hour is 45 minutes Mr panasuk took 45 minutes

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What is the average rate of change of the function over the interval x = 0 to x = 6? f(x) = (2x - 1) / (3x + 5)
Sedaia [141]

Answer:

The average rate of change of the function over the interval x = 0 to x = 6 is \frac{34}{195}.

Step-by-step explanation:

Geometrically speaking, the average rate of change (r) of the function over a given interval is determined by equation of secant line, that is:

r = \frac{f(b)-f(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds.

f(a), f(b) - Function evaluated at lower and upper bounds.

If we know that f(x) = \frac{2\cdot x -1 }{3\cdot x + 5}, a = 0 and b = 6, then the average rate of change of the function over the interval is:

f(a) = \frac{2\cdot (0)-1}{3\cdot (0) +5}

f(a) = -\frac{1}{5}

f(b) = \frac{2\cdot (6)-1}{3\cdot (6)+5}

f(b) = \frac{11}{13}

r = \frac{\frac{11}{13}-\left(-\frac{1}{5} \right) }{6-0}

r = \frac{34}{195}

The average rate of change of the function over the interval x = 0 to x = 6 is \frac{34}{195}.

5 0
3 years ago
What is the slope of the line represented by the points in the table?
strojnjashka [21]

Answer: D

Step-by-step explanation: I just took the quiz, it should work

7 0
2 years ago
Read 2 more answers
What is a balanced equation using numbers 9,7,2,1,6?
Tom [10]
How about 9+6=(7·2)+1  15=15
7 0
3 years ago
PLEASE HELP ASAP, I WILL GIVE 40 POINTS IF THE RIGHT ANSWER, AND BRAINLEST, ASAP
Julli [10]

Answer:

5/52

Step-by-step explanation:

There are 52 cards in a deck, with 26 red and 26 black cards. There are 2 red ones, 2 black threes, and 1 six of hearts. The # of favorable outcomes is 2 + 2 + 1 = 5, so the answer is 5/52.

7 0
1 year ago
Let f(x)=x^2+5x−36. Enter the x-intercepts of the quadratic function in the boxes.___and__
Zolol [24]

Given

f(x)=x^2+5x-36

8 0
1 year ago
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