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rodikova [14]
3 years ago
7

Choose the correct coefficients to balance the following equation: __Zn + __HCl Imported Asset __ZnCl2 + __H2.

Chemistry
1 answer:
N76 [4]3 years ago
3 0

Answer:

option b = 1,2,1,1

Explanation:

Chemical equation:

Zn + HCl → ZnCl₂ + H₂

Balanced chemical equation:

Zn + 2HCl → ZnCl₂ + H₂

There are two atoms of hydrogen one atom of zinc and 2 atoms of chlorine on both side of equation.

The common oxidation state of zinc is +2 while tat of chlorine is -1 that's why two chlorine atoms combine with one atom of zinc to accept two electrons.

Zn⁺²Cl₂²⁻ negative and positive charges are equal in magnitude that's why over all compound is neutral.

While two atoms of hydrogen combine with each other through covalent bond by shearing the electrons.

The oxidation state of zinc is increased from 0 to +2 so it gets oxidized while that of chlorine is -1 to -2 is chlorine gets reduced.

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Mg(OH)2 + 2 HBr à MgBr2 + 2 H2O
AnnyKZ [126]

Explanation:

The balanced equation of the reaction is given as;

Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)

1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?

From the reaction;

2 mol of HBr produces 1 mol of  MgBr2

Converting to masses using;

Mass = Number of moles * Molar mass

Molar mass of HBr = 80.91 g/mol

Molar mass of MgBr2 = 184.113 g/mol

This means;

(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2

18.3g would produce x

161.82 = 184.113

18.3 = x

x = (184.113 * 18.3 ) / 161.82 = 20.8 g

2. How many moles of H2O will be produced from 18.3 grams of HBr?

Converting the mass to mol;

Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol

From the reaction;

2 mol of HBr produces 2 mol of H2O

0.226 mol would produce x

2 =2

0.226 = x

x = 0.226 * 2 / 2 = 0.226 mol

3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?

From the reaction;

2 mol of HBr reacts with 1 mol of Mg(OH)2

18.3g of HBr =  0.226 mol

2 = 1

0.226 = x

x = 0.226 * 1 /2

x = 0.113 mol

5 0
3 years ago
what is the concentration of a dextrose solution prepared by diluting 14 ml of a 1.0 m dextrose solution to 25 ml using a 25 ml
allsm [11]

The concentration of a dextrose solution prepared by diluting 14 ml of a 1.0 M dextrose solution to 25 ml using a 25 ml volumetric flask is 0.56M.

Concentration is defined as the number of moles of a solute present in the specific volume of a solution.

According to the dilution law, the degree of ionization increases on a dilution and it is inversely proportional to the square root of concentration. The degree of dissociation of an acid is directly proportional to the square root of a volume.

M₁V₁=M₂V₂

Where, M₁=1.0M, V₁=14ml, M₂=?, V₂=25ml

Rearrange the formula for M₂

M₂=(M₁V₁/V₂)

Plug all the values in the formula

M₂=(1.0M×14 ml/25 ml)

M₂=14 M/25

M₂=0.56 M

Therefore, the concentration of a dextrose solution after the dilution is 0.56M.

To know more about dilution

brainly.com/question/18566203

#SPJ4

6 0
11 months ago
19. I accidentally mixed bleach and ammonia when cleaning one day. It released 55 liters of deadly chlorine (CI) gas. How many g
user100 [1]
55,000 grams
Hope this helps you out :)
3 0
2 years ago
Are there more metals or nonmetals on the periodic table?
bogdanovich [222]

Answer:yes

Explanation:

I think so

6 0
3 years ago
Read 2 more answers
What is the angle between two of the nitrogen-hydrogen bonds in the ammonium (NH4+) ion?
Arlecino [84]

Answer:

109° 27'

Explanation:

The ammonium ion is tetrahedral in shape, all the HNH bonds are exactly at the tetrahedral bond angle since there are only bond pairs in the structure and no lone pairs. Recall that lone pairs decrease the bond angke from the ideal value in a tetrahedron due to higher repulsion.

8 0
3 years ago
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