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rodikova [14]
3 years ago
7

Choose the correct coefficients to balance the following equation: __Zn + __HCl Imported Asset __ZnCl2 + __H2.

Chemistry
1 answer:
N76 [4]3 years ago
3 0

Answer:

option b = 1,2,1,1

Explanation:

Chemical equation:

Zn + HCl → ZnCl₂ + H₂

Balanced chemical equation:

Zn + 2HCl → ZnCl₂ + H₂

There are two atoms of hydrogen one atom of zinc and 2 atoms of chlorine on both side of equation.

The common oxidation state of zinc is +2 while tat of chlorine is -1 that's why two chlorine atoms combine with one atom of zinc to accept two electrons.

Zn⁺²Cl₂²⁻ negative and positive charges are equal in magnitude that's why over all compound is neutral.

While two atoms of hydrogen combine with each other through covalent bond by shearing the electrons.

The oxidation state of zinc is increased from 0 to +2 so it gets oxidized while that of chlorine is -1 to -2 is chlorine gets reduced.

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One year ago, you sold a put option on 100,000 euros with an expiration date of 1 year. you received a premium on the put option
pochemuha
There are two problems for this question:1. What is the total dollar amount of your profit and loss:
Put option premium is equal to 0.04 per unit.
The exercise price is 1.22
One option contract is 100,000
Selling price is 1.20
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Net profit is = 0.02 x 100,000 = 2,000 – 80 = 1,920

2. Now undertake that as an alternative of taking a position in the put option one year ago, you sold a future's contract on 100,000 euros with a payment date of one year.
Find the total dollar amount of your profit or loss.
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Explanation:

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How many grams of water will be produced from 50 g hydrogen reacting with 50 g oxygen?
DanielleElmas [232]

We need to first come up with a balanced equation:


4H+O_{2} → 2H_{2}O


We know that the molar ratio of hydrogen to oxygen to water now is 4:1:2.


Converting the amount of grams given to moles is as follows:


Hydrogen: \frac{1mole}{1.008g}*50g=49.6mol


Oxygen: \frac{1mole}{15.999g}*50g=3.125mol


We know now that the limiting reactant is oxygen. We can then know that the number of moles of water are produced are double the number of moles of oxygen used due to the ratio that we established at the beginning - 4:1:2.


So we now can use 6.25 moles of water as the amount produced.


Then we convert moles of water to grams:


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Now we know that there are 112.59g of water produced when we start with 50g of hydrogen and 50g of water.

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