Answer:
Moles NH₃: 0.0593
0.104 moles of N₂ remain
Final pressure: 0.163atm
Explanation:
The reaction of nitrogen with hydrogen to produce ammonia is:
N₂ + 3 H₂ → 2 NH₃
Using PV = nRT, moles of N₂ and H₂ are:
N₂: 1atmₓ3.0L / 0.082atmL/molKₓ273K = 0.134 moles of N₂
H₂: 1atmₓ2.0L / 0.082atmL/molKₓ273K = 0.089 moles of H₂
The complete reaction of N₂ requires:
0.134 moles of N₂ × (3 moles H₂ / 1 mole N₂) = <em>0.402 moles H₂</em>
That means limiting reactant is H₂. And moles of NH₃ produced are:
0.089 moles of H₂ × (2 moles NH₃ / 3 mole H₂) = <em>0.0593 moles NH₃</em>
Moles of N₂ remain are:
0.134 moles of N₂ - (0.089 moles of H₂ × (1 moles N₂ / 3 mole H₂)) = <em>0.104 moles of N₂</em>
And final pressure is:
P = nRT / V
P = (0.104mol + 0.0593mol)×0.082atmL/molK×273K / 5.0L
<em>P = 0.163atm</em>
2H2O➡2H2+O2 is the correct balanced equation of decomposition
Because decomposition means a molecule breaking down in to segments
Answer:
can u give us the options
The energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.
<h3>Energy and wavelength of light</h3>
The energy and wavelength of light are related by the formula given below:
- Energy = hc/λ
- where, E = energy
- h = Planck's constant
- c = velocity of light
- λ = wavelength of light
<h3>Calculating the energy of the light</h3>
From the data provided:
- h = 6.63 × 10^-34 Js
- c = 3.0 × 10^8 m/s
- λ = 415 nm = 4.15 × 10^-7 m
E = (6.63 × 10^-34 × 3.0 × 10^8 m/s)/4.15 × 10^-7 m
E = 4.79 × 10^-19 J
Energy of light is 4.79 × 10^-19 J
Compared with the ionization energy of silver, the energy of the light is far less.
Therefore, the energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.
Learn more about about ionization energy and energy of light at: brainly.com/question/14596067
