The density of silver is 10.5 g/cm3.
Resources found in lithosphere: gold and iron etc
Resources found in atmosphere: Water vapor, gases etc.
Two independent variables could change at the same time, and you would not know which variable affected the dependent variable
1.6456 x 10^3 (ten to the third power)
Answer:
Q = 3440Kj
Explanation:
Given data:
Mass of gold = 2kg
Latent heat of vaporization = 1720 Kj/Kg
Energy required to vaporize 2kg gold = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg
by putting values,
Q= 2kg × 1720 Kj/Kg
Q = 3440Kj
