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stich3 [128]
2 years ago
8

A whale comes to the surface to breathe and then dives at an angle of 20.0 ∘ below the horizontal (see the figure (Figure 1)). I

f the whale continues in a straight line for 160 m , how deep is it? How far has it traveled horizontally?
Physics
1 answer:
Bond [772]2 years ago
7 0

Answer:

The question is missing something it doesn't say how fast down its going and doesn't show the figure sorry for wasting an answer

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When you look ahead while driving, it is best to:
vodka [1.7K]
I think its [B]
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active and passive secruity measures are employed to identify, detect, classify and analyze possible threats inside of which zon
Juli2301 [7.4K]

Answer:

Assessment zone

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It is the assessment zone in various security zones where active and passive security measures are employed to identify, detect, classify and analyze possible threats inside the assessment zones.

8 0
3 years ago
I cant solve this problem, and our teacher said that this would be in the test we'll have tomorrow, can someone help me?
Ad libitum [116K]

Answer:

d = 11.1 m

Explanation:

Since the inclined plane is frictionless, this is just a simple application of the conservation law of energy:

\frac{1}{2} m {v}^{2}  = mgh

Let d be the displacement along the inclined plane. Note that the height h in terms of d and the angle is as follows:

\sin(15)  =  \frac{h}{d}  \\ or \: h = d \sin(15)

Plugging this into the energy conservation equation and cancelling m, we get

{v}^{2}  = 2gd \sin(15)

Solving for d,

d =  \frac{ {v}^{2} }{2g \sin(15) }  =  \frac{ {(7.5 \:  \frac{m}{s}) }^{2} }{2(9.8 \:  \frac{m}{ {s}^{2} })(0.259)}   \\ = 11.1 \: m

3 0
3 years ago
What is frost weddging
kiruha [24]
Freeze wedging<span> is caused by the repeated freeze-thaw. </span>Frost wedging<span> occurs as the result of 9 % expansion of water when it is converted to ice. Cracks filled with water are forced further apart when it freezes. cycle.</span>
4 0
3 years ago
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Mazyrski [523]

Answer:

The diameter of the bull-wheel is 3.82

Explanation:

Given that,

Velocity = 2.0 m/s

Angular velocity = 10 rev/m

\omega=10\times\dfrac{2\pi}{60}

\omega=1.0472\ rad/s

We need to calculate the diameter of bull-wheel

Using formula of angular velocity

v= r\omega

r=\dfrac{v}{\omega}

Put the value into the formula

r=\dfrac{2.0}{1.0472}

r=1.91\ m

The diameter of the bull-wheel

D=2r

D=2\times1.91

D=3.82\ m

Hence, The diameter of the bull-wheel is 3.82 m.

6 0
3 years ago
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