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2 years ago

8

A whale comes to the surface to breathe and then dives at an angle of 20.0 ∘ below the horizontal (see the figure (Figure 1)). I

f the whale continues in a straight line for 160 m , how deep is it? How far has it traveled horizontally?

1 answer:

Bond [772]2 years ago

7 0

Answer:

The question is missing something it doesn't say how fast down its going and doesn't show the figure sorry for wasting an answer

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A bridge is constructed above a river such that an object dropped from it will reach the river after 4.5 seconds. A precocious y

Sloan [31]

Answer:

Vf = 11.04 m/s

Explanation:

First, we consider free fall motion with zero initial velocity. Using 2nd equation of motion:

h = Vi t + (1/2)gt²

where,

h = height of bridge = ?

Vi = Initial Speed = 0 m/s

t = time taken = 4.5 s

g = 9.8 m/s²

Therefore,

h = (0 m/s)(4.5 s) + (1/2)(9.8 m/s²)(4.5 s)²

Therefore,

h = 99.225 m

Now, we consider the forced motion when the youth throws the ball with some negative initial energy:

Vi = - Vi

t = 3 s

h = 99.225 m

Therefore,

99.225 m = - Vi(3 s) + (1/2)(9.8 m/s²)(3 s)²

Vi = (- 99.225 m + 44.145 m)/3 s

Vi = - 18.36 m/s

Now, we use this in 1st equation of motion for final velocity:

Vf = Vi + gt

Vf = -18.36 m/s + (9.8 m/s²)(3 s)

Therefore,

<u>Vf = 11.04 m/s</u>

7 0

3 years ago

A cannon ball is launched off a 100 m cliff horizontally with an initial horizontal velocity (Vx) of 50 m/s.

denis-greek [22]

We have the equation of motion $s = ut+\frac{1}{2} at^2$ , where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.

Here displacement = 100 m, Initial velocity = 0 m/s, acceleration = 9.81 $m/s^2$

Substituting

$100 = 0*t+\frac{1}{2} *9.8*t^2\\ \\ 100 = 4.9t^2\\ \\ t = 4.52 seconds$

A cannon ball is launched off a 100 m cliff horizontally with an initial horizontal velocity (Vx) of 50 m/s will take 4.52 seconds to reach the ground.

7 0

3 years ago

The momentum of an ostrich is calculated to be 5,400 kg*km / hr Its mass is known to be 120 kg. Was the ostrich moving or standi

Dmitry [639]

The correct answer to the question is : The ostrich is motion.

EXPLANATION:

As per the question, the momentum of ostrich P = 5400 Kg. Km/hr.

The mass of the ostrich m = 120 Kg.

The momentum of a body is defined as the product of mass with velocity.

Mathematically P = mv.

The velocity of the ostrich v is calculated as -

v = $\frac{P}{m}$

= $\frac{5400}{120}\ Km/hr$

= 45 Km/hr

Hence, the ostrich is in motion as it is moving with a velocity of 45 Km/hr.

7 0

3 years ago

Read 2 more answers

Ronch [10]

Answer:

Current in a parallel circuit = 0.61 amps (Approx)

Explanation:

Given:

Voltage V = 6 volt

Two resistors = 17.2 , 22.4 in parallel circuit

Find:

Current in a parallel circuit

Computation:

1/R = 1/r1 + 1 / r2

1/R = 1/17.2 + 1 / 22.4

R = 9.73 ohms (Approx)

Current in a parallel circuit = V / R

Current in a parallel circuit = 6 / 9.73

Current in a parallel circuit = 0.61 amps (Approx)

4 0

3 years ago

Consult Multiple-Concept Example 11 for background material relating to this problem. A small rubber wheel on the shaft of a bic

Papessa [141]

Answer:

$Emf=24.4V$

Explanation:

From the question we are told that:

Angular speed $\omega=40*\omega'$

Radius $r=0.33m$

No. Turns $N=163$

Area $A= 3.23 * 10^{-3} m^2$

Magnetic field. $B=0.0948T$

Acceleration $a=0.60m/s^2$

Time $t=6.72s$

Generally the equation for momentum is mathematically given by

$\omega'=\omega_o+\frac[a}{r}t$

$\omega'=0+\frac{0.60}{0.33}*6.72$

$W=12.22rad/s^2$

Therefore

$\omega=Aw$

$\omega=12.22*40$

$\omega=488.7rads/s$

Generally the equation for Peak emf is mathematically given by

$Emf=NBA \omega$

$Emf=163*0.0948* 3.23 * 10^{-3} m^2*488.7rads/s$

$Emf=24.4V$

3 0

3 years ago