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natali 33 [55]
2 years ago
7

Write a paragraph using -Multicellular ,Unicellular ,Tissue ,Xylem ,Organ , System In a paragraph

Physics
1 answer:
Gennadij [26K]2 years ago
5 0

Answer:

    I sometimes use a tissue when blowing my nose, I mean, my organs are made up of cells and tissue. I am also a multicellular organism, as I am made up of multiple cells; however, I am not a unicellular being, as, again, I am made up of multiple cells. I don't think I possess a xylem because I am not a plant, but plants do! They use them to transfer water around and stuff. Me being a human and all, I am a large system of different organs, tissue, and such.

Explanation: i used the words provided

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the three major scales used to measure earthquakes are Mercalli scale Richard scale and magnitude scale
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 False; the three major scales used to measure earthquakes are the Mercalli Scale, the Richter Scale, and the Magnitude Scale. I hope this helps!
3 0
3 years ago
A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 4.50 s, it is at
wariber [46]

Answer:

See it in the pic

Explanation:

See it in the pic

7 0
3 years ago
TRUE OR FALSE Light can travel through materials that you cannot see through, like wood or aluminum foil.
Keith_Richards [23]

i think its uhh......tralse

8 0
2 years ago
A rock is launched vertically upward by a slingshot. The elastic band of the slingshot accelerates the rock from rest to 40 m/s
eimsori [14]

Answer:

0.016 s

Explanation:

Initial velocity, u = 0

use the third equation of motion to find the acceleration of the rock.

2as=v^2-u^2\\a = \frac{40^2-0}{2\times0.1} =8000 m/s^2

Net displacement in the vertical direction would be zero. y = 0

Use second equation:

s=ut+\frac{1}{2}at^2\\0=0+\frac{1}{2}(8000)t^2\\t= 0.016 s

Thus, the rock will return to its initial release point in 0.016 s.

5 0
3 years ago
A 0.27 kg rock is projected from the edge of the top of a building with an initial velocity of 11.7 m/s at an angle 58◦ above th
tester [92]

Incomplete question.The complete question is

A 0.27 kg rock is projected from the edge of  the top of a building with an initial velocity of  11.7 m/s at an angle 58  above the horizontal. Due to gravity, the rock strikes the ground at  a horizontal distance of 15.9 m from the base  of the building.  How tall is the building? Assume the  ground is level and that the side of the building is vertical. The acceleration of gravity is  9.8 m/s

Answer:

Total height of the building =6.78 m

Explanation:

v = 11.7 m/s

Horizontal component of velocity = v x cos 58 = 11.7*cos 58 = 6.2 m/s

Total time of flight = Horizontal distance / Horizontal component of velocity = 15.9 / 6.2 = 2.56 sec.

Vertical component of velocity = v x sin 58 = 11.7 x sin 58 = 9.92 m/s

Time taken to reach maximum height = Vertical component of velocity / g = 9.92 / 9.81 = 1.01 sec.

Hence, Time taken to reach ground from maximum height = 2.56 - 1.01 = 1.55 sec.

Hence, Maximum height from ground = 0.5 x g x t^2 = 0.5 x 9.81 x 1.55^2 = 11.78 m

Maximum height from the top of building = 0.5 x 9.81 x 1.01^2 = 5 m

Hence, Total height of the building = 11.78 m - 5 m = 6.78 m

6 0
3 years ago
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