A 110 V power line is protected by a 15 A fuse. What is the maximum number of 400 W lamps that can be simultaneously operated in
1 answer:
Answer:
Total number of lamps will be 4
Explanation:
We have given power of the lamp W = 400 watt
Potential difference across the lamp V=110 volt
We know that power is equal to
So
Total current is given 15 A
As it is given that lamps are connected in parallel so total current is the sum of current through each lamp
So number of lamp will be
As the lamp can not be in negative
So total number of lamps will be 4
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Answer:
The combined speed of the woman and the skateboard is 6.67 m/s.
Explanation:
It is given that,
Mass of woman, m₁ = 60 kg
Speed of woman, v = 10 m/s
The woman jumps onto a giant skateboard of mass, m₂ = 30 kg
Let V is the combined speed of the woman and the skateboard. It can be calculated using the conservation of momentum as :
On solving the above equation we get V = 6.67 m/s
So, the combined speed of the woman and the skateboard is 6.67 m/s. Hence, this is the required solution.