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2 years ago

According to the Law of Reflection, the angle of incidence

Physics

1 answer:

Elan Coil [88]2 years ago

8 0

Answer:

Explanation:

this is because the law of reflection states that the angle of incidence equals to the angle of the reflection.

hope this helps, if not please report it

someone else can try it

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A solution is a homogeneous mixture of one or more solutes dissolved in a solvent. A specific volume of solvent is only able to

Luba_88 [7]

<h3><u>Answer;</u></h3>

C. Supersaturated

<h3><u>Explanation</u>;</h3>

Solutions are homogeneous mixtures that are created by mixing a solute and a solvent. Solute is the substance present in smaller amounts that dissolves in a solvent such as water which is the substance present in larger amount.
A solution, can be<u> unsaturated, saturated or supersaturated. An unsaturated solution</u> is a solution that contains less solute that can be dissolved, it doesn't contain the maximum amount of solute.
<u>A saturated solution</u> is a solution containing the maximum amount of solute that can be dissolved at a given temperature. Any additional solute will remain undissolved in the container.
<u>A supersaturated solution</u> is a solution created when a solution is carefully cooled because it contains more solute than the solubility allows.

7 0

3 years ago

Read 2 more answers

Malia has developed Type II Diabetes. When she eats, her body

AlladinOne [14]

Answer:

The correct option is c.

Explanation:

Metabolism is a sum of anabolic and catabolic reactions. The body's inability to produce/synthesize enough insulin is the cause of type II diabetes. Generally, metabolism is the process in which most compounds (proteins, carbohydrates and lipids) are produced (anabolism) or broken down (catabolism) in the body. Insulin is a protein that can be produced in less amount due to metabolic disorder in the body.

Maria's disease means she already has an exponentially high amount of blood sugar against the required insulin to balance it out, hence the disease already slowed down her rate of metabolism (catabolism) of blood sugar EXCEPT she decides to increase of metabolism by medication and exercise.

3 0

3 years ago

Describes the relationship between the free energy change, the reaction quotient, and the equilibrium constant.

LUCKY_DIMON [66]

<u>Explanation:</u>

Reaction quotient is defined as the ratio of the concentration of the products and reactants of a reaction at any point of time with respect to some unit. It is represented by the symbol <em>Q</em>.

The ratio of the concentration of products and reactants of a reaction in equilibrium with respect to some unit is said to be equilibrium constant expression. It is represented by the symbol <em>K</em>.

The relationship between Gibbs free energy change and reaction quotient of the reaction is:

$\Delta G=\Delta G^o+RT ln Q$ ......(1)

where,

$\Delta G$ = Gibbs free energy change

$\Delta G^o$ = Standard Gibbs free energy change

R = Gas constant

T = Temperature

At equilibrium, the free energy change of the reaction becomes 0 and standard Gibbs free energy change can be related to the equilibrium constant by the equation:

$\Delta G^o=-RT ln Q$ ...(2)

4 0

3 years ago

Is more of north america north or south of the tropic of cancer

TEA [102]

Explanation:

This parallel is located in the northern hemisphere, located at a latitude of 23 ° 26′12.2 ″ (or 23,43671 °) north of the equator. Approximately in the geographic half of Mexico, crossing the states of Baja California Sur, Sinaloa, Durango, Zacatecas, San Luis, Potosí, Nuevo León, Tamaulipas. Therefore, there is more of north america, at north of the tropic of cancer.

6 0

2 years ago

In a flying ski jump, the skier acquires a speed of 110 km/h by racing down a steep hill and then lifts off into the air from a

matrenka [14]

Answer:

Approximately $\displaystyle\rm \left[ \begin{array}{c}\rm191\; m\\\rm-191\; m\end{array}\right]$ .

Explanation:

Consider this $45^{\circ}$ slope and the trajectory of the skier in a cartesian plane. Since the problem is asking for the displacement vector relative to the point of "lift off", let that particular point be the origin $(0, 0)$ .

Assume that the skier is running in the positive x-direction. The line that represents the slope shall point downwards at $45^{\circ}$ to the x-axis. Since this slope is connected to the ramp, it should also go through the origin. Based on these conditions, this line should be represented as $y = -x$ .

Convert the initial speed of this diver to SI units:

$\displaystyle v = \rm 110\; km\cdot h^{-1} = 110 \times \frac{1}{3.6} = 30.556\; m\cdot s^{-1}$ .

The question assumes that the skier is in a free-fall motion. In other words, the skier travels with a constant horizontal velocity and accelerates downwards at $g$ ( $g \approx \rm -9.81\; m\cdot s^{-2}$ near the surface of the earth.) At $t$ seconds after the skier goes beyond the edge of the ramp, the position of the skier will be:

$x$ -coordinate: $30.556t$ meters (constant velocity;)
$y$ -coordinate: $\displaystyle -\frac{1}{2}g\cdot t^{2} = -\frac{9.81}{2}\cdot t^{2}$ meters (constant acceleration with an initial vertical velocity of zero.)

To eliminate $t$ from this expression, solve the equation between $t$ and $x$ for $t$ . That is: express $t$ as a function of $x$ .

$x = 30.556\;t\implies \displaystyle t = \frac{x}{30.556}$ .

Replace the $t$ in the equation of $y$ with this expression:

$\begin{aligned} y = &-\frac{9.81}{2}\cdot t^{2}\\ &= -\frac{9.81}{2} \cdot \left(\frac{x}{30.556}\right)^{2}\\&= -0.0052535\;x^{2}\end{aligned}$ .

Plot the two functions:

$y = -x$ ,
$\displaystyle y= -0.0052535\;x^{2}$ ,

and look for their intersection. Refer to the diagram attached.

Alternatively, equate the two expressions of $y$ (right-hand side of the equation, the part where $y$ is expressed as a function of $x$ .)

$-0.0052535\;x^{2} = -x$ ,

$\implies x = 190.35$ .

The value of $y$ can be found by evaluating either equation at this particular $x$ -value: $x = 190.35$ .

$y = -190.35$ .

The position vector of a point $(x, y)$ on a cartesian plane is $\displaystyle \left[\begin{array}{l}x \\ y\end{array}\right]$ . The coordinates of this skier is approximately $(190.35, -190.35)$ . The position vector of this skier will be $\displaystyle\rm \left[ \begin{array}{c}\rm191\\\rm-191\end{array}\right]$ . Keep in mind that both numbers in this vectors are in meters.

4 0

3 years ago