Answer:
Theoretical yield = 3.52 g
Percent yield =65.34%
Explanation:
Given data:
Mass of HgO = 46.8 g
Theoretical yield of O₂ = ?
Percent yield of O₂ = ?
Actual yield of O₂ = 2.30 g
Solution:
Chemical equation:
2HgO → 2Hg + O₂
Number of moles of HgO = mass/ molar mass
Number of moles of HgO = 46.8 g / 216.6 g/mol
Number of moles of HgO = 0.22 mol
Now we will compare the moles of HgO with oxygen.
HgO : O₂
2 : 1
0.22 : 1/2×0.22 = 0.11 mol
Theoretical yield:
Mass of oxygen = number of moles × molar mass
Mass of oxygen = 0.11 mol × 32 g/mol
Mass of oxygen = 3.52 g
Percent yield :
Percent yield = actual yield / theoretical yield × 100
Percent yield = 2.30 g/ 3.52 g × 100
Percent yield =65.34%
<h3>Answer:</h3>
221.90 g.mol⁻¹
<h3>Explanation:</h3>
The mass of contained by a molecule is known as molecular mass. It is the sum of atomic weights of the elements contained by the molecule. In given case Iodine Pentafluoride has a chemical formula,
IF₅
The atomic weights of each element are as;
Iodine = 126.90 g.mol⁻¹
Fluorine = 19.00 g.mol⁻¹
As there are five atoms of Fluorine so, we will multiply the atomic weight of Fluorine by five and that of Iodine by one as there is only one Iodine atom.
Therefore,
Molecular Mass of IF₅ = (1 × 126.90 g.mol⁻¹) + (5 × 19.00 g.mol⁻¹)
Molecular Mass of IF₅ = (126.90 g.mol⁻¹) + (95.00 g.mol⁻¹)
Molecular Mass of IF₅ = 221.90 g.mol⁻¹
I’m not sure but I’m sure it’s b please thank me
