The concentration of hydrogen can be shown as:
[H+ ] = 3 * 10-5 M
pH can be determined as:
pH = - log [H+ ]
= - log (3 * 10-5)
= 4.53
Thus the pH of solution is 4.53
Answer:
<h2>The answer is 3.0 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
![volume = \frac{mass}{density} \\](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7Bmass%7D%7Bdensity%7D%20%20%5C%5C%20)
From the question
mass of aluminum = 8.1 g
density = 2.7 g/mL
It's volume is
![volume = \frac{8.1}{2.7} \\](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7B8.1%7D%7B2.7%7D%20%20%5C%5C%20)
We have the final answer as
<h3>3.0 mL</h3>
Hope this helps you
Answer:
Iron is oxidized while chlorine is reduced.
Explanation:
The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Consider the following reaction:
2FeCl₂ + Cl₂ → 2FeCl₃
in this reaction the oxidation state of iron is increased from +2 to +3. That's why iron get oxidized and it is reducing agent because it reduced the chlorine. The chlorine is reduced from -2 to -3 and it is oxidizing agent because it oxidized the iron.
2Fe⁺²Cl₂⁻²
2Fe⁺³Cl₃⁻³
The iron atom gives it three electrons to three atoms of chlorine and gain positive charge while chlorine atom accept the electron and form anion.
Answer: 72.93 litres
Explanation:
Given that:
Volume of gas (V) = ?
Temperature (T) = 24.0°C
Convert 24.0°C to Kelvin by adding 273
(24.0°C + 273 = 297K)
Pressure (P) = 1.003 atm
Number of moles (n) = 3 moles
Molar gas constant (R) is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
1.003 atm x V = 3.00 moles x 0.0821 atm L K-1 mol-1 x 297K
1.003 atm•V = 73.15 atm•L
Divide both sides by 1.003 atm
1.003 atm•V/1.003 atm = 73.15 atm•L/1.003 atm
V = 72.93 L
Thus, the volume of the gas is 72.93 litres
<h3>Balanced equation :
2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)</h3><h3>Further explanation</h3>
Alkanes are saturated hydrocarbons that have single bonds in chains
General formula for alkanes :
![\tt \large{\bold{C_nH_{2n+2}}](https://tex.z-dn.net/?f=%5Ctt%20%5Clarge%7B%5Cbold%7BC_nH_%7B2n%2B2%7D%7D)
Hydrocarbon combustion reactions (specifically alkanes)
![\large {\box {\bold{C_nH _ (_2_n _ + _ 2_) + \dfrac {3n + 1} {2} O_2 \Rightarrow nCO_2 + (n + 1) H_2O}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cbox%20%7B%5Cbold%7BC_nH%20_%20%28_2_n%20_%20%2B%20_%202_%29%20%2B%20%5Cdfrac%20%7B3n%20%2B%201%7D%20%7B2%7D%20O_2%20%5CRightarrow%20nCO_2%20%2B%20%28n%20%2B%201%29%20H_2O%7D%7D%7D)
So that the burning of ethane with air (oxygen):
![\tt C_2H_6+\dfrac{7}{2}O_2\rightarrow 2CO_2+3H_2O](https://tex.z-dn.net/?f=%5Ctt%20C_2H_6%2B%5Cdfrac%7B7%7D%7B2%7DO_2%5Crightarrow%202CO_2%2B3H_2O)
2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)
or we can use mathematical equations to solve equilibrium chemical equations by giving the coefficients for each compound involved in the reaction
C₂H₆ (g) + aO₂ (g) ⟶ bCO₂ (g) + cH₂O (ℓ)
C : left 2, right b ⇒ b=2
H: left 6, right 2c⇒ 2c=6⇒ c= 3
O : left 2a, right 2b+c⇒ 2a=2b+c⇒2a=2.2+3⇒2a=7⇒a=7/2