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3 years ago

An organic solvent has a density of 1.31g/ml. What volume is occupied by 50.0g of the liquid?

Chemistry

1 answer:

vesna_86 [32]3 years ago

8 0

Answer:

38.16 mL

Solution:

Data Given;

Density = 1.31 g/mL

Mass = 50 g

Volume = ?

Formula Used;

Density = Mass ÷ Volume

Solving for Volume,

Volume = Mass ÷ Density

Putting values,

Volume = 50 g ÷ 1.31 g.mL⁻¹

Volume = 38.16 mL

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What is the pH of a solution with an H3O+ concentration of 5.67 x 10-4 M?

Valentin [98]

Answer:

Explanation:

The pH of a solution can be found by using the formula

$pH = - log [ { H_3O}^{+}]$

From the question we have

$ph = - log(5.67 \times {10}^{ - 4} ) \\ = 3.2464$

We have the final answer as

Hope this helps you

3 0

2 years ago

Which description of salt is a physical property? (2 points)

jarptica [38.1K]

Product of mixing acids and bases describes salt is a physical property.

Product of mixing acids and bases

<u>Explanation:</u>

When an acid and a base are put together, they respond to kill the corrosive and base properties, creating a salt which portrays the physical property. The physical properties of table salt will be: Salt is a white cubic gem. At the point when the salt is unadulterated it clear.

It likewise shows up in white, dim or caramel shading relying on immaculateness. It is unscented yet has a solid salty taste. Fundamental salts contain the conjugate base of a feeble corrosive, so when they break down in the water, they respond with water to yield an answer with a pH more than 7.0.

8 0

2 years ago

46.6 grams of mercury II sulfate (HgSO4) reacts with an excess of sodium Chloride (NaCl). How many grams of mercury II chloride

slega [8]

Answer:

$m_{HgCl_2}=42.7gHgCl_2$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$HgSO_4+2NaCl\rightarrow HgCl_2+Na_2SO_4$

In such a way, the mercury II sulfate (molar mass 296.65g/mol) is in a 1:1 molar ratio with the mercury II chloride (molar mass 271.52g/mol), for that reason the stoichiometry to find mass in grams of mercury II chloride turns out:

$m_{HgCl_2}=46.6gHgSO_4*\frac{1molHgSO_4}{296.65 gHgSO_4}*\frac{1molHgCl_2}{1molHgSO_4} *\frac{271.52gHgCl_2}{1molHgCl_2} \\\\m_{HgCl_2}=42.7gHgCl_2$