1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natta225 [31]
3 years ago
5

Fill in the Blanks

Physics
1 answer:
Simora [160]3 years ago
8 0
Blank 1) axe
blank 2) less
blank 3) more
You might be interested in
If you have 10.0 g of a substance that decays with a half-life of 14 days, then how much will you have after 42 days?
Nat2105 [25]
The formula for the mass that remains:
m=m_0 \times (\frac{1}{2})^\frac{t}{T}
m₀ - the initial mass, t - time, T - the half-life

m_0=10 \ g \\
T=14 \ d \\
t=42 \ d \\ \\
m=10 \times (\frac{1}{2})^\frac{42}{14}=10 \times (\frac{1}{2})^3=10 \times \frac{1}{8}=10 \times 0.125=1.25

The answer is c. 1.25 g.
6 0
3 years ago
Two neutron stars are separated by a distance of 1.0 x 1012 m. They each have a mass of 1.0 x 1028 kg and a radius of 1.0 x 103
son4ous [18]

To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

Gravitational potential energy can be defined as

PE = -\frac{GMm}{R}

As M=m, then

PE = -\frac{Gm^2}{R}

Where,

m = Mass

G =Gravitational Universal Constant

R = Distance /Radius

PART A) As half its initial value is u'=2u, then

U = -\frac{2Gm^2}{R}

dU = -\frac{2Gm^2}{R}

dKE = -dU

Therefore replacing we have that,

\frac{1}{2}mv^2 =\frac{Gm^2}{2R}

Re-arrange to find v,

v= \sqrt{\frac{Gm}{R}}

v = \sqrt{\frac{6.67*10^{-11}*1*10^{28}}{1*10^{12}}}

v = 816.7m/s

Therefore the  velocity when the separation has decreased to one-half its initial value is 816m/s

PART B) With a final separation distance of 2r, we have that

2r = 2*10^3m

Therefore

dU = Gm^2(\frac{1}{R}-\frac{1}{2r})

v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}

v = \sqrt{6.67*10^{-11}*10^{28}(\frac{1}{2*10^3}-\frac{1}{10^{12}})}

v = 1.83*10^7m/s

Therefore the velocity when they are about to collide is 1.83*10^7m/s

7 0
3 years ago
The main illustration in the video shows the life track of a one-solar mass star. Each point along this track represents _______
REY [17]

Each point along the track of one solar mass star represents the star's surface temperature and luminosity at one time.

<h3>What is the one-solar mass star?</h3>

A star having a mass equal to the mass of the Sun is called a one-solar mass star.

Its life track shows the luminous intensity as well as the surface temperature.

Learn more about one-solar mass star.

brainly.com/question/14984575

#SPJ1

7 0
2 years ago
Help me plsssss<br> help me plsssss
Zepler [3.9K]
Answer:


It is d. 0.80
Trust me i got it right took it and got it right
4 0
2 years ago
Student pushes a 50 N block across the floor for a distance of 15 m how much work was done to move the block
Talja [164]

Answer:

750 J

Explanation:

We have a student that pushes a 50N block  across the floor for a distance of 15m. The question is asking how much work was done to move the block.

To solve this, we must know that we are looking for a certain thing called joules. And to get the answer, we must follow the formula of W = FS

F being the force and S being the distance.

W = FS

W = (50)(15)

W = 750

Therefore, 750 joules is our answer.

7 0
3 years ago
Other questions:
  • Identify the four main divisions of the peripheral nervous system and explain each one's function.
    13·2 answers
  • A wave travels at a constant speed. How does the frequency change if the wavelength increases by a factor of 2?
    14·2 answers
  • The roller-coaster car shown in fig. 6-41 (h1 = 30 m, h2 = 12 m, h3 = 20 m), is dragged up to point 1 where it is released from
    8·1 answer
  • If a bird applies a 5 N upward force on a branch to lift the branch of ground to a
    11·1 answer
  • A sharp edged orifice with a 50 mm diameter opening in the vertical side of a large tank discharges under a head of 5m. If the c
    13·1 answer
  • BWhat Do You Get When You Multiply An Object's mass times the acceleration?
    13·1 answer
  • On which planet would a 15.0 kg object weigh the most? How much would a 15.0 kg object weigh on that planet? Round the answer to
    13·2 answers
  • In which image below is the angle of refraction the greatest?
    8·1 answer
  • This graph indicates that the acceleration between 2.00 and 4.00 seconds is the same as that between 12.00 and 14.00 seconds.
    9·1 answer
  • A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from po
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!