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An EM wave has a wave length of 956 m, What type of electromagnetic waves is this wave

Assoli18 [71]

The electromagnetic spectrum allows finding the result for the question of type of electromagnetic wave has a wavelength of 956 nm

The wave is in the near infrared range.

The electromagnetic wave is an oscillation of electric fields and magnets field that sustain each other, this wave time has the characteristics that it can travel without a material medium, for which they are of extreme importance.

Consequently the spectrum of electromagnetic waves to each part has been given a different name second to its use, for example

Range Name

Ultraviolet light 200 to 400 nm

Visible light 400 to 700 nm

Infrared light (heat ) 700 nm to 1 mm

The latter is subdivided into:

Near infrared 700 nm to 1000 nm (1 μm)

Medium infrared 1 μm to 30 μm

Far infrared 50 μm to 1000 μm

It indicates that the wavelength of the measured radiation is 956 nm, therefore it is in the near infrared range.

Learn more about the electromagnetism spectrum here: brainly.com/question/23727978

6 0

2 years ago

A theory is a way of explaining observations. true or false.

Natasha_Volkova [10]

I think its true. hope this helps.

5 0

3 years ago

Read 2 more answers

A 120-V rms voltage at 60.0 Hz is applied across an inductor, a capacitor, and a resistor in series. If the rms value of the cur

klemol [59]

Answer:

The impedance of this circuit is 200 ohm.

Explanation:

Given that,

rms voltage = 120 v

Frequency = 60.0 Hz

rms current = 0.600 A

We need to calculate the impedance

Using formula of impedance

$Z=\dfrac{V_{rms}}{I_{rms}}$

Where, $V_{rms}$ = rms voltage

$I_{rms}$ = rms current

Z= impedance

Put the value into the formula

$Z=\dfrac{120}{0.600}$

$Z=200\ Omega$

Hence, The impedance of this circuit is 200 ohm.

8 0

3 years ago

What can be found by counting the number of troughs per second in a wave diagram? amplitude direction frequency speed wavelength

Nutka1998 [239]

The period T is time it takes for one complete cycle or from "trough to trough" so the reverse is trough per sec = 1/T = frequency

6 0

3 years ago

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Two 10 kg pucks head straight towards each other with velocities of 10 m/s and -20 m/s. They collide and stick together. Calcula

RUDIKE [14]

The final velocity of the two pucks is -5 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum.

In fact, in absence of external force, the total momentum of the two pucks before and after the collision must be conserved - so we can write:

$m_1 u_1 + m_2 u_2 = (m_1 +m_2)v$

where

$m_1 = m_2 = m = 10 kg$ is the mass of each puck

$u_1 = 10 m/s$ is the initial velocity of the 1st puck

$u_2 = -20 m/s$ is the initial velocity of the 2nd puck

v is the final velocity of the two pucks sticking together

Re-arranging the equation and solving for v, we find:

$mu_1 + mu_2 = (m+m)v\\u_1 + u_2 = 2v\\v=\frac{u_1+u_2}{2}=\frac{10-20}{2}=-5 m/s$

Learn more about momentum:

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8 0

2 years ago