For this problem, we will assume that:
the right direction has a positive sign
the left direction has a negative sign
Note: You can assume the opposite but take care during the substitution
The law of conservation of momentum states that the total momentum of the system remains constant unless an external force acts on this system.
This law can be translated into the following equation:
m1v1 + m2v2 = m1v1' + m2v2'
where:
m1 is mass of first object = 1.2 kg
v1 is the initial velocity of first object = 0 m/sec (starts from rest)
m2 is the mass of the second object = 1.8 kg
v2 is the initial velocity of second object = 0 m/sec (starts from rest)
v1' is the final velocity of the first object that we need to find
v2' is the final velocity of the second object = 2 m/sec
Substitute with the givens in the above equation to get v1' as follows:
m1v1 + m2v2 = m1v1' + m2v2'
(1.2)(0) + (1.8)(0) = (1.2)(v1') + (1.8)(2)
0 =1.2v1' + 3.6
1.2v1' = -3.6
v1' = -3 m/sec
This means that the final velocity of the first object is 3 m/sec in the left direction
Answer:
B
Explanation:
The enzime's active site bindes to the substrate.... when an enzime binds to a substrate it forms a enzime-substrate complex
Answer:
I2>I1
Explanation:
This problem can be solved by using the parallel axis theorem. If the axis of rotation of a rigid body (with moment of inertia I1 at its center of mass) is changed, then, the new moment of inertia is gven by:
where M is the mass of the object and d is the distance of the new axis to the axis of the center of mass.
It is clear that I2 is greater than I1 by the contribution of the term Md^2.
I2>I1
hope this helps!!
Answer:
(a) Girl acceleration = 0.15 m/s², (b) Sled acceleration = 0.93 m/s²
Explanation:
Given:
M1=Mass of girl = 43 Kg
M2= mass of Sled = 7.1 Kg
Force F= 6.6 N
To Find (a) a1 = girl acceleration (b) a2 = sled acceleration
Solution:
F1 = F2 = F (Newton's 3rd Law)
F=ma (Newton's 2nd Law)
(a) F = M1a1
⇒a1 = F/M1 = 6.6 N / 43 Kg = 0.15 m/s²
(b) a2 = F / M2 = 6.6 N / 7.1 Kg = 0.93 m/s²
