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4vir4ik [10]
3 years ago
8

Earth’s axis slowly but continuously points in different directions. True or False

Physics
1 answer:
Dafna11 [192]3 years ago
3 0

True

Earth’s axis slowly but continuously points in different directions in a phenomenon called <u>axial precession</u>.

Explanation:

The tilt of the earth is not constant at 23.5 degrees.  Rather the earth's axis precesses in a cycle of approximately 25,772 years. This slow precession can have an apparent effect on climate on earth, especially in conjunction with <em>Milankovitch cycles</em> like aphelion and perihelion. Due to the axial precession, the poles can be facing to or away from the sun during aphelion or perihelion. This consequently can affect the cover ice sheet and glacier in the poles due to the time of exposure to sun rays.

Learn More:

For more on Milankovitch cycles check out;

brainly.com/question/4122364

brainly.com/question/685555

#LearnWithBrainly

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Which statement best defines constructive interference? O Energy reflects back toward the source of its power. O Two waves with
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Answer: two waves with identical crests and troughs meet

Explanation:

My teacher gave me the answer

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2 years ago
Give a calculate answer to show that the two values (English system and metric system) for the Planck Constant are equivalent.
Nataly_w [17]

Answer:

Given values of Planck Constant are equivalent in English system and metric system.

Explanation:

Value of Planck's constant is given in English system as 4.14 x 10⁻¹⁵eV s.

Converting this in to metric system .

We have 1 eV = 1.6 x 10⁻¹⁹ J

Converting

     4.14 x 10⁻¹⁵eV s = 4.14 x 10⁻¹⁵x 1.6 x 10⁻¹⁹ = 6.63 x 10⁻³⁴ Joule s

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3 years ago
Will Mark Brainliest if Correct PLZ!!!!! A bullet is shot at some angle above the horizontal at an initial velocity of 87m/s on
qaws [65]

Answer:

≅50°

Explanation:

We have a bullet flying through the air with only gravity pulling it down, so let's use one of our kinematic equations:

Δx=V₀t+at²/2

And since we're using Δx, V₀ should really be the initial velocity in the x-direction. So:

Δx=(V₀cosθ)t+at²/2

Now luckily we are given everything we need to solve (or you found the info before posting here):

  • Δx=760 m
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  • t=13.6 s
  • a=g=-9.8 m/s²; however, at 760 m, the acceleration of the bullet is 0 because it has already hit the ground at this point!

With that we can plug the values in to get:

760=(87)(cos\theta )(13.6)+\frac{(0)(13.6^{2}) }{2}

760=(1183.2)(cos\theta)

cos\theta=\frac{760}{1183.2}

\theta=cos^{-1}(\frac{760}{1183.2})\approx50^{o}

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