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zhannawk [14.2K]
3 years ago
11

BRAINLIEST AND 20 POINTS! Guys, I literally have no idea.

Chemistry
2 answers:
Tatiana [17]3 years ago
7 0
The answer is 0.65 mol
yuradex [85]3 years ago
5 0
.65 because the relationship between moles of zinc to moles of silver is 1:2. Just divide 1.30 by two to get .65
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The average dosage of oxcarbazepine for an epileptic child between the ages of 4 and 16 is 9.00 mg per 1 kg of body weight (9.00
melamori03 [73]
Convert the child weight (37.3 pounds) to kilograms

37.3 lb x 0.453 kg /1lb = "A kg"

multiply the dose (9.00mg/kg) by the weight of the child to find how much you need to give him

A kg * 9.00 mg/1kg = "B mg" 

calculate the mL of suspension dividing the "B mg" by the concentration of the suspension 60.0 mg/mL

B mg * 1mL/ 60.0 mg = C mL <span>oxcarbazepine</span>
8 0
3 years ago
Read 2 more answers
How many grams of carbon are in 0.24 moles of carbon?
Ronch [10]

Answer:

I'm converting this if I could remember how

2.882568

2 110321/ 125000

T-T sorry if I'm wrong I have bad memory

so I recommend not using my answer at all,

if that is even how y'all write it.

4 0
2 years ago
A gas system contains 2.00 moles of O2 and CO2 gas, has an initial temperature of 25.0 oC and is under 1.00 atm of pressure. If
Ainat [17]

Answer:

V_2=52.2L

Explanation:

Hello there!

In this case, by bearing to to mind the given conditions, it is firstly possible to determine the initial volume of the closed system via the ideal gas equation:

PV=nRT\\\\V=\frac{2.00mol*0.08206\frac{atm*L}{mol*K}*298.15K}{1.00 atm} \\\\V=48.9L

Which is V1 in the Charles' law:

\frac{T_2}{V_2} =\frac{T_1}{V_1}

And of course, T1 is 298.15 (25+273.15). Therefore, by solving for V2 as the final volume, we obtain:

V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{48.9L*(45+273.15)K}{(25+273.15)K}  \\\\V_2=52.2L

Best regards!

8 0
3 years ago
I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
ioda

Answer:

Where are the question's???

Explanation:

7 0
2 years ago
What is the balanced symbol equation for magnesium chloride + sodium carbonate --&gt; magnesium carbonate + sodium chloride
Semenov [28]

Answer:

MgCl₂+ Na₂CO₃ ==> MgCO₃ + NaCl

From a quick observation

You see that the right hand side of the eqn is deficient of Sodium and Chlorine

Simply Add a Coefficient of 2 to NaCl to balance it with the left.

Your answer now becomes

MgCl₂ + Na₂CO₃ ==> MgCO₃ + 2NaCl.✅

3 0
2 years ago
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