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makvit [3.9K]
2 years ago
11

Which of the following statements is true for radioactive reactions:

Chemistry
2 answers:
sasho [114]2 years ago
8 0

Answer:

d) Nucleus of the element does not change during the react

hope it helps (^^)

# Cary on learning

Ghella [55]2 years ago
3 0
D) nucleus of the element does not change during the react
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Is this anwser correct
Hoochie [10]
Yes it is correct I think not for sure
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3 years ago
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Which of the following is an example of energy causing motion?
Verdich [7]

Answer:

the answer is c

Explanation:

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3 years ago
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A gas occupies 25,3 mL at a pressure of 152 kPa. Find the volume if the pressure is
sleet_krkn [62]

Answer:

This is under gas laws. check it out

3 0
3 years ago
Since acids have 1 more proton (H+ - ions) than base, and the acid gives it away, doesn't that mean that they switch roles? Acid
andreev551 [17]

Answer:

In an acid-base equilibrium, acid becomes a conjugate base and base becomes a conjugate acid.

Explanation:

Let's remember the Bronsted-Lowry theory to answer this specific question. According to the theory, acid is a proton donor, while a base is a proton acceptor.

Consider an acid in a form HA (aq) and base in a form of B (aq). Since acid is a proton donor, it will donate its hydrogen ion to the base, B. The resultant products would be A^{-} (aq) and BH^{+} (aq).

Remember that an acid-base reaction is an equilibrium reaction. This means we may also look at this proton transfer reaction from the product side towards the reactants. Summarizing what has been said, we may write the equilibrium as:

HA (aq) + B (aq) ⇄ BH^{+} (aq) + A^{-} (aq)

Now acid, HA, donates a proton to become a conjugate base. The conjugate base, if we look from the reverse equation side, is actually a base, since it can accept a proton to become HA. Similarly, B accepts a proton to become a conjugate acid. Looking from the reverse reaction, it can now donate a proton, so in reality we can consider it a base.

To summarize, your logic is correct.

6 0
3 years ago
Ammonium Iodide dissociates reversibly to ammonia and hydrogen iodide:
NeTakaya

Answer:

The partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C Is 0.103 atm.

The correct option is A.

Explanation;

NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°C

NH4I(s)= 0.215

NH3(g)=0.103

HI(g)Kp=0.112

Therefore = 0.103 +0.112= 0.215

Therefore the partial pressure of ammonia at equilibrium is 0.103 atm

7 0
3 years ago
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