Answer:
11.4 moles of H₂SO₄ are needed to completely react the 7.6 moles of Al
Explanation:
The equation indicates that 2 moles of aluminum react to 3 moles of sulfuric acid in order to produce 1 mol of aluminum sulfate and 3 moles of hydrogen gas.
The reaction is: 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
This question can be solved with an easy rule of three. Ratio in the reaciton is 2:3, so we propose:
2 moles of Al react with 3 moles of sulfuric acid
Then, 7.6 moles of Al will react with 11.4 moles of H₂SO₄
Mass of sulfur combined - 4.69 g
Mass of gas produced is 15.81 g, therefore mass of fluorine is (15.81-4.69) = 11.12 g
Number of sulfur moles - 4.69 g/32 g/mol = 0.15 mol
Number of fluorine moles - 11.12 g/ 19 g/mol = 0.585 mol
divide both by least number of moles
S - 0.15/0.15 = 1
F - 0.585/0.15 = 3.9 rounded off is 4
ratio of S to F = 1:4Therefore formula of the gas is SF₄
Answer:
Explanation: See images below for explanation
