Answer:
no of formula unit = 
Explanation:
atomic mass of CaCl2 = 40 + 2×35.5 = 111 g.
no of formula unit = no of moles × Avagadro number
=
<em>I am going to use first-person pronouns for this drop of water</em>
[ Start ] Liquid
I start out as a drop of water among other drops of water in the ocean. I am currently a liquid as I can change shape easily but I do not float up.
[ Middle ] Gas
The sun feels very hot. From the heat I turn into a gas, specifically water vapor, and float up into the sky.
[ Middle x 2 ] Solid
In the sky I meet up with a lot of my past friends. We form a cloud, and as we grow heavier (the more the merrier) we start to fall down. It is extremely cold now, so we fall down as a solid, also known as hail or snow.
[ End ] Liquid
We hit the ocean again as we fall from the sky. I'm so happy to be back home as a water drop again!
Have a nice day! - <u>Please note this is very simplified</u>
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
11.2L / 22.4L/mol = . 5 mol H2 40g / 160g/mol = . 25 mol Br2.
Answer:
The molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.HOW TO CALCULATE MOLARITY:The molarity of a solution can be calculated by dividing the number of moles by its volume. That is;Molarity = no. of moles ÷ volumeAccording to this question, 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide. The molarity is calculated as follows:Molarity = 0.50mol ÷ 2LMolarity = 0.25MTherefore, the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.Learn more about molarity at: brainly.com/question/2817451
Explanation:
Mark me brainliest please!!! I spent a lot of time on this!!
Answer:
Cr₂S₃
Explanation:
From the question given above, the following data were obtained:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Empirical formula =?
Next, we shall determine the mass of sulphur (S) in the compound. This can be obtained as follow:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Mass of sulphur (S) =?
Mass of S = (Mass of chromium sulfide) – (Mass of Cr)
Mass of S = 1.2888 – 0.67
Mass of S = 0.6188 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of Cr = 0.67 g
Mass of S = 0.6188 g
Divide by their molar mass
Cr = 0.67 / 52 = 0.013
S = 0.6188 / 32 = 0.019
Divide by the smallest
Cr = 0.013 / 0.013 = 1
S = 0.019 / 0.013 = 1.46
Multiply by 2 to express in whole number
Cr = 1 × 2 = 2
S = 1.46 × 2 = 3
Therefore, the empirical formula of the compound is Cr₂S₃
