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steposvetlana [31]
3 years ago
6

What parts of a shark fossilize other than its teeth? (has EVERYTHING to do with my last question)

Physics
1 answer:
dmitriy555 [2]3 years ago
3 0
Other parts of the shark that are fossilized is the cartilage, the fins, the spine, and the vertebrae. 
Hope this helped! :D
(Again XD)
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Which of the following correctly arranges the planets by the size of their diameter in increasing order?
valentinak56 [21]
Increasing Order..
So, it's from the little one into the biggest one..

My Answer is
C: Mercury < Earth < Saturn < Jupiter

What Shape of The Earth ?
Is it Round or Flat ?
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7 0
3 years ago
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The relationship between frequency and period is...
Kazeer [188]

\\

Frequency, f, is how many cycles of an oscillation occur per second and is measured in cycles per second or hertz (Hz). The period of a wave, T, is the amount of time it takes a wave to vibrate one full cycle. These two terms are inversely proportional to each other: f = 1/T and T = 1/f.

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7 0
2 years ago
1. A piece of metal weighs 50.0 N in air, 36.0 N in water, and 41.0 N in an unknown
denis23 [38]

Answer:

a) 3.37 x 10^{3} kg/m^3

b) 6.42kg/m^{3}

Explanation:

a) Firstly we would calculate the volume of the metal using it`s weight in air and water , after finding the weight we would find the density .

Weight of metal in air = 50N = mg implies the mass of metal is 5kg.

Now the difference of weight of the metal in air and water = upthrust acting on it = volume (metal) p (liquid) g = V (1000)(10) = 14N. So volume of metal piece = 14 x 10^{-4}  kg/m^{3}. So density of metal = mass of metal / volume of metal = 5 / 14 x 10^{-4}  kg/m^{3} = 3.37 x 10^{3} kg/m^3

b) Water exerts a buoyant force to the metal which is 50−36 = 14N, which equals the weight of water displaced. The mass of water displaced is 14/10 = 1.4kg Since the density of water is 1kg/L, the volume displaced is 1.4L. Hence, we end up with 3.57kg/l. Moreover, the unknown liquid exerts a buoyant force of 9N. So the density of this liquid is 6.42kg/m^{3}

3 0
3 years ago
PLEASE HELP can not find the answer
romanna [79]
I think the answer would be letter B.
7 0
3 years ago
An car has an acceleration of 8.0 m/s/s. How much time is needed to reach a velocity of 30 m/s from
polet [3.4K]

Answer:

3.75s

Explanation:

a = 8.0 m/s V = 30 m/s U = 0 m/s t = ?

t = V - U/a

t = 30 - 0/8

t = 30/8 = 15/4

t = 3.75s

5 0
3 years ago
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