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ZanzabumX [31]
2 years ago
11

Please help!!!

Physics
1 answer:
Brilliant_brown [7]2 years ago
5 0

Answer:

All of the inventors can be characterized as problem-solvers.

Explanation:

Took the practice

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Answer:

exercise dailyyy

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Explanation:

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3 years ago
Objects that gain elastic energy by being stretched out
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Rubber band, elastic, spring
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At left A red ball in a box with arrows pointing away from the ball in all directions. In the middle, a blue ball in a box with
MAVERICK [17]

Answer:

first one is b 2nd one is a 3rd is c and the 4th one is c also

Explanation: have a nice day

6 0
2 years ago
Read 2 more answers
The volume of an object as a function of time is calculated by v = At3+B÷t where t is time measured in seconds and v is in cubic
madam [21]

Answer:

A = m³/s³ = [L]³/[T]³ = [L³T⁻³]

B = m³s = [L³T]

Explanation:

We have the equation:

V = At³ + B/t

where, the dimensions of each variable are as follows:

V = m³ = [L]³

t = s = [T]

substituting these in equation, we get:

m³ = A(s)³ + B/s

for the homogeneity of the equation:

A(s)³ = m³

<u>A = m³/s³ = [L]³/[T]³ = [L³T⁻³]</u>

Also,

B/s = m³

<u>B = m³s = [L³T]</u>

3 0
3 years ago
A 0.750 kg block is attached to a spring with spring constant 17.5 N/m. While the block is sitting at rest, a student hits it wi
Dmitriy789 [7]

Answer:

a

 A =  0.081 \  m

b

The value is  u =  0.2569 \  m/s

Explanation:

From the question we are told that

   The mass is  m  =  0.750 \ kg

   The spring constant is  k  =  17.5 \  N/m

    The instantaneous speed is  v  =  39.0 \  cm/s= 0.39 \  m/s

    The position consider is  x =  0.750A  meters from equilibrium point

   

Generally from the law of  energy conservation we have that

        The kinetic energy induced by the hammer  =  The energy stored in the spring

So

          \frac{1}{2} *  m * v^2  =  \frac{1}{2}  *  k  *  A^2

Here a is the amplitude of the subsequent oscillations

=>      A =  \sqrt{\frac{m *  v^ 2 }{ k} }

=>      A =  \sqrt{\frac{0.750 *  0.39 ^ 2 }{17.5} }

=>       A =  0.081 \  m

Generally from the law of  energy conservation we have that

The kinetic energy  by the hammer  =  The energy stored in the spring at the point considered   +   The kinetic energy at the considered point

             \frac{1}{2}  * m *  v^2 = \frac{1}{2}  * k x^2 + \frac{1}{2}  * m *  u^2

=>          \frac{1}{2}  * 0.750 *  0.39^2 = \frac{1}{2}  * 17.5* 0.750(0.081 )^2 + \frac{1}{2}  * 0.750 *  u^2

=>          u =  0.2569 \  m/s

3 0
2 years ago
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