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marta [7]
3 years ago
7

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.60 m/s. The car is a distan

ce d away. The bear is 39.3 m behind the tourist and running at 5.00 m/s. The tourist reaches the car safely. What is the maximum possible value for d
Physics
1 answer:
In-s [12.5K]3 years ago
7 0

Answer:

101 meters

Explanation:

Distance traveled by the tourist:

d = 3.60 m/s × t

Distance traveled by the bear:

d + 39.3 m = 5.00 m/s × t

Substitute:

3.6 t + 39.3 = 5 t

39.3 = 1.4 t

t = 28.1

d = 101

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Gravity anything with mass as gravity we know the earth has gravity because you and I are standing on earth and not floating off
Paraphin [41]

Answer:

F=mg

Explanation:

Close to Earth's surface, the force of gravity that pulls an object towards the ground is

F=mg (2)

where

m is the mass of the object

g is the acceleration due to gravity, which is 9.81 m/s^2 close to Earth's surface

This is an approximation of the general formula of gravity valid only close to Earth's surface. The more general formula is

F=G\frac{Mm}{r^2} (1)

where

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m is the object's mass

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8 0
3 years ago
Gravitational potential energy is a form of potential energy
Gre4nikov [31]
True because it has "falling" ability
5 0
3 years ago
An electric dipole is formed from ± 5.0 nC point charges spaced 3.0 mm apart. The dipole is centered at the origin, oriented alo
Ymorist [56]

Answer:

The electric field strength at point (x,y) = ( 20 mm ,0cm) is =<u>16321.0769 N/C</u>

The electric field strength at point (x,y) = (0cm, 20 mm) is =<u>35321.58999 N/C</u>

Explanation:

Question: What is the electric field strength at point (x,y) = ( 20 mm ,0cm)?

Answer:

The electric field at any given point of the dipole is given as:

E= (KP) ÷ (r^2 + a^2)^3/2

Where:

K = 9x10^9 Nm^2/c^2 (coloumb constant)

P = (0.003) (5x10^-9c) which is the movement of the dipole

(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.

r= the point, in the question above is 20mm = 0.02m

Now, the electric field, E can be calculated by putting the values in the formula above:

E = (KP) ÷ (r^2 + a^2)^3/2

= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2

= 0.135 ÷ (8.271513x10^-6)

=<u>16321.0769 N/C</u>

 Question: What is the electric field strength at point (x,y) = (0cm, 20 mm )?

Answer:

Here, the electric field, E= 2krp ÷ (r^2 - a^2)^2

E= 2 (9x10^9 Nm^2/c^2) (0.02m) (0.003 m) (5x10^-9c) ÷ [(0.02m)^2 - (0.003)^2]^2

= 0.0054 ÷  0.000000152881

=<u>35321.58999 N/C</u>

8 0
3 years ago
What can pressure be measured by?
SOVA2 [1]
'Pressure' is  (force) / (area).

The only choice with those units is #1 .
5 0
4 years ago
Pls help will give brainlest​
Karo-lina-s [1.5K]

Respon

lqiudos ciopatmibes

ly  apsamtios ccoriendor sabe r

llpop

io.

7 0
3 years ago
Read 2 more answers
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