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2 years ago

What mirror diameter gives 0.1 arc second resolution for infrared radiation of wavelength 2 micrometers?

Physics

1 answer:

Irina18 [472]2 years ago

7 0

Answer:

The diameter of mirror $5\times10^{-6}\ m$

Explanation:

Given that,

Wavelength = 2 μm

Resolution = 0.1

We need to calculate the diameter of mirror

Using formula of resolution

$resolution=0.25\times\dfrac{wavelength}{diameter}$

$diameter =0.25\times\dfrac{wavelength}{resolution}$

Put the value into the formula

$diameter=0.25\times\dfrac{2\times10^{-6}}{0.1}$

$diameter = 0.000005\ m$

$diameter = 5\times10^{-6}\ m$

Hence, The diameter of mirror $5\times10^{-6}\ m$

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What name is given to the process that occurs when light passes from air to water?

-Dominant- [34]

Answer:

Refraction

Explanation:

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3 years ago

A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication

koban [17]

Answer:

r = 4.24x10⁴ km.

Explanation:

To find the radius of such an orbit we need to use Kepler's third law:

$\frac{T_{1}^{2}}{T_{2}^{2}} = \frac{r_{1}^{3}}{r_{2}^{3}}$

<em>where T₁: is the orbital period of the geosynchronous Earth satellite = 1 d, T₂: is the orbital period of the moon = 0.07481 y, r₁: is the radius of such an orbit and r₂: is the orbital radius of the moon = 3.84x10⁵ km. </em>

From equation (1), r₁ is:

$r_{1} = r_{2} \sqrt[3] {(\frac{T_{1}}{T_{2}})^{2}}$

$r_{1} = 3.84\cdot 10^{5} km \sqrt[3] {(\frac{1 d}{0.07481 y \cdot \frac{365 d}{1 y}})^{2}}$

$r_{1} = 4.24 \cdot 10^{4} km$

Therefore, the radius of such an orbit is 4.24x10⁴ km.

I hope it helps you!

3 0

3 years ago

A net force of 20 N acting on a wooden block produces an

Ymorist [56]

Answer:

From the second law of motion:

F = ma

we are given that the force applied on the block is 20N and the block accelerates at an acceleration of 4 m/s/s

So, F= 20N and a = 4 m/s/s

Replacing the variables in the equation:

20 = 4* m

m = 20 / 4

m = 5 kg

5 0

3 years ago

Two speakers, one directly behind the other, are each generating a 240-Hz sound wave. What is the smallest separation distance b

AveGali [126]

Answer:

The smallest separation distance between the speakers is 0.71 m.

Explanation:

Given that,

Two speakers, one directly behind the other, are each generating a 240-Hz sound wave, f = 240 Hz

Let the speed of sound is 343 m/s in air. The speed of sound is given by the formula as :

$v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{343\ m/s}{240\ Hz}\\\\\lambda=1.42\ m$

To produce destructive interference at a listener standing in front of them,

$d=\dfrac{\lambda}{2}\\\\d=\dfrac{1.42}{2}\\\\d=0.71\ m$

So, the smallest separation distance between the speakers is 0.71 m. Hence, this is the required solution.

3 0

3 years ago

Read 2 more answers

A 3600 kg rocket traveling at 2900 m/s is moving freely through space on a journey to the moon. The ground controllers find that

Nana76 [90]

Answer:

m=417.24 kg

Explanation:

Given Data

Initial mass of rocket M = 3600 Kg

Initial velocity of rocket vi = 2900 m/s

velocity of gas vg = 4300 m/s

Θ = 11° angle in degrees

To find

m = mass of gas

Solution

Let m = mass of gas

first to find Initial speed with angle given

Vi=vi×tanΘ...............tan angle

Vi= 2900m/s × tan (11°)

Vi=563.7 m/s

Now to find mass

m = (M ×vi ×tanΘ)/( vg + vi tanΘ)

put the values as we have already solve vi ×tanΘ

m = (3600 kg ×563.7m/s)/(4300 m/s + 563.7 m/s)

m=417.24 kg

7 0

3 years ago