A military jet cruising at an altitude of 12.0km and speed of 1300./kmh burns fuel at the rate of 46.2/Lmin. How would you calcu
1 answer:
Answer:
2,452.12 L of fuel the jet consumes on a 1150 km mission.
Explanation:
Speed of the jet = 1300 km/h
1 hour = 60 minutes
Rate at which jet consumes fuel = 46.2 L/min
Distance covered by jet by consuming 1 liter fuel or mileage = R
R =
The amount of fuel the jet consumes on a 1150 km mission will = V
Amount of fuel =
2,452.12 L of fuel the jet consumes on a 1150 km mission.
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Answer:
1.327 g Ag₂CrO₄
Explanation:
The reaction that takes place is:
- 2AgNO₃(aq) + K₂CrO₄(aq) → Ag₂CrO₄(s) + 2KNO₃(aq)
First we need to <em>identify the limiting reactant</em>:
We have:
- 0.20 M * 50.0 mL = 10 mmol of AgNO₃
- 0.10 M * 40.0 mL = 4 mmol of K₂CrO₄
If 4 mmol of K₂CrO₄ were to react completely, it would require (4*2) 8 mmol of AgNO₃. There's more than 8 mmol of AgNO₃ so AgNO₃ is the excess reactant. <em><u>That makes K₂CrO₄ the limiting reactant</u></em>.
Now we <u>calculate the mass of Ag₂CrO₄ formed</u>, using the <em>limiting reactant</em>:
- 4 mmol K₂CrO₄ *
= 1326.92 mg Ag₂CrO₄
- 1326.92 mg / 1000 = 1.327 g Ag₂CrO₄
Answer:
The answer is
<h2>3.68 g/mL</h2>Explanation:
The density of a substance can be found by using the formula
<h3>From the question
mass of substance = 12.50 g
volume = 3.4 mL
The density of the substance is
We have the final answer as
<h3>3.68 g/mL</h3>Hope this helps you