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marishachu [46]
3 years ago
5

Ben starts walking along a path at 4 mi/h. one and a half hours after ben leaves, his sister amanda begins jogging along the sam

e path at 6 mi/h. how long will it be before amanda catches up to ben?
Physics
1 answer:
zvonat [6]3 years ago
7 0

<u>Answer:</u>

After 3 hours Amanda catch up to Ben.

<u>Explanation:</u>

 Speed of Ben = 4 mi/h

 Speed of Amanda = 6 mi/h

 Time after Amanda starts after Ben leaves = 1.5 hours.

 Let the time taken for them to catch up be t hours.

 Distance traveled by Ben in time (t+1.5) =  4*(t+1.5)

 Distance traveled by Amanda in time t = 6*t

 Equating both the distances

     4*(t+1.5)=  6*t

     2t = 6

       t = 3 hours

    So after 3 hours Amanda catch up to Ben.

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Which does not affect the gravitational potential energy of an object? mass height speed acceleration due to gravity
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Answer:

Speed

Explanation:

The answer is speed. It doesn’t affect potential energy because it’s associated with position. But since kinetic energy is associated with motion speed affects it.

8 0
3 years ago
Please help. It’s probably easy
iragen [17]
I believe it’s 60km/h

I divided the total distance (120 km) by the time it took to get there (2h) to get this.
7 0
3 years ago
A student is doing a lab experiment in which she uses diffraction to measure the width of a shaft of her hair. She shines a 530
professor190 [17]

Answer:

.09 mm

Explanation:

In case of diffraction by single slit with width a the width of central maxima is given below

width = 2 λD/a

where λ is wavelength of light , D is distance of screen , a is width o slit

substituting the given values

14 x 10⁻³ = \frac{2\times530\times10^{-9}\times1.2}{a}

a = .09 mm

b) If a is greater , width of central maxima will be less wide.

7 0
4 years ago
The distance between the first and fifth minima of a single-slit diffraction pattern is 0.350 mm with the screen 39.0 cm away fr
rjkz [21]

Answer: a) the width is 2.54 mm

b) the angle is 0.012°

Explanation:

we have the equation:

λ = zw/(L*m)

Where is the distance for the middle of the screen, L is the distance to the screen, w is the widht of the slit and λ is the wavelength.

now we can isolate z and get:

z = λL*m/w

and the distance between the 5 minimum and the first one is 0.035mm

then:

0.035mm = λL*5/w - λL*1/w = λL*4/w

now we can solve it for w.

0.35mm = 570nm*39.0cm*4/w

now, we have all diferent units, lets use nanometers.

1cm = 1x10^-2 m

1mm = 1x10^-3 m

1nm = 1x10^-9m

then: 1 cm = 1x10^7 nm

         1 mm = 1x10^6 nm

then we have:

0.35x10^6 nm = 570nm*39.0x10^7 nm*4/w

w = (570nm*39.0x10^7 nm*4)/0.35x10^6 nm =(570nm*39.0*10*4)/0.35

w = 2540571.4 nm

it is a bigg number, let's write it in milimeters:

w = (2540571.4/10^6) mm = 2.54 mm

the first minimum can be obtained by the equation w*sinθ = mλ by using m = 1

then we have:

2540571.4 nm*sinθ = 570 nm

sinθ = 570/2540571.4 = 0.000224

θ = asin(0.00022) = 0.012°

5 0
3 years ago
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