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klasskru [66]
3 years ago
15

Which of the following types of reactions would decrease the entropy within a cell?

Physics
1 answer:
kifflom [539]3 years ago
7 0

Answer:

dehydration reactions

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car travels 80 meters due north in 12 seconds then the car turns around and travels 30 Mi do South in 4 seconds calculate the av
Zinaida [17]

Answer:

1) 3.1 m/s

2) 7 m/s

Explanation:

Distance due north = 80 m

Distance due south = 30 m

Distance between north and south = (80 - 30) m = 50 m

Total time = (12 + 4) sec = 16 sec

1) Average speed = 50/16 = 3.1 m/s

2) Average velocity = Total distance/total time = (80 + 30) m/16 s = 110/16 = 7 m/s

8 0
3 years ago
The diagram shows a heat engine. In which area of the diagram is unusable thermal energy detected?
Marat540 [252]
Nope, I disagree with the former answer. The answer is definitely Z. <u>W area</u> (boxed with red outline) is represented as the hot reservoir while <u>Z area</u> is the cold reservoir (boxed with blue outline). X area is the heat engine itself and Y area is the work produced from thermal energy from hot reservoir. Typically, all heat engines lose some heat to the environment (based from the second law of thermodynamics) that is symbolically illustrated by the lost energy in the cold reservoir. This lost thermal energy is basically the unusable thermal energy. The higher thermal energy lost, the less efficient your heat engine is. 
7 0
3 years ago
Read 2 more answers
Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pictured. What
IgorLugansk [536]

Answer:

Frequency is 213.04\ s^{-1}.

Explanation:

Distance between source 1 from the receiver , S_1 =\sqrt{10^2+22^2}=24.17\ m.

Distance between source 2 from the receiver , S_2=\sqrt{5^2+22^2}=22.56\ m.

Now ,

Path difference , r = S_1-S_2=24.17-22.56=1.61\ m.

We know, for constructive interference path difference should be integral multiple of wavelength .  

Therefore, r=n\times \lambda

It is given that n = 1,

Therefore, \lambda=1.61\ m.

Frequency can be found by , \nu=\dfrac{v}{\lambda}= \dfrac{343}{1.61}=   213.04\ s^{-1} .

Hence, this is the required solution.

5 0
3 years ago
Eac of the two Straight Parallel Lines Each of two very long, straight, parallel lines carries a positive charge of 24.00 m C/m.
Cloud [144]

Answer:

The magnitude of the electric field at a point equidistant from the lines is 4.08\times10^{5}\ N/C

Explanation:

Given that,

Positive charge = 24.00  μC/m

Distance = 4.10 m

We need to calculate the angle

Using formula of angle

\theta=\sin^{-1}(\dfrac{\dfrac{d}{2}}{2d})

\theta=\sin^{-1}(\dfrac{1}{4})

\theta=14.47^{\circ}

We need to calculate the magnitude of the electric field at a point equidistant from the lines

Using formula of electric field

E=\dfrac{2k\lambda}{r}\times2\cos\theat

Put the value into the formula

E=\dfrac{2\times9\times10^{9}\times24.00\times2\times10^{-6}\cos14.47}{2.05}

E=408094.00\ N/C

E=4.08\times10^{5}\ N/C

Hence, The magnitude of the electric field at a point equidistant from the lines is 4.08\times10^{5}\ N/C

6 0
3 years ago
What happens when a magenta light is shone on a green surface?
Sedbober [7]

Answer:

When Magenta light is shown on a green surface, it looks black.

Explanation:

It absorbs the Magenta light and also reflects none of the light.

5 0
3 years ago
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