Answer:
The work done by the hoop is equal to 5.529 Joules.
Explanation:
Given that,
Mass of the hoop, m = 96 kg
The speed of the center of mass, v = 0.24 m/s
To find,
The work done by the hoop.
Solution,
The initial energy of the hoop is given by the sum of linear kinetic energy and the rotational kinetic energy. So,
I is the moment of inertia, 
Since, 
Finally it stops, so the final energy of the hoop will be, 
The work done by the hoop is equal to the change in kinetic energy as :
W = -5.529 Joules
So, the work done by the hoop is equal to 5.529 Joules. Therefore, this is the required solution.
Answer:
Total strain when the stress was equal to 210 MPa = 0.101
Explanation:
See attached pictures.
Work, Kinetic Energy and Potential Energy
6.1 The Important Stuff 6.1.1 Kinetic Energy
For an object with mass m and speed v, the kinetic energy is defined as K = 1mv2
2
(6.1)
Kinetic energy is a scalar (it has magnitude but no direction); it is always a positive number; and it has SI units of kg · m2/s2. This new combination of the basic SI units is
known as the joule:
As we will see, the joule is also the unit of work W and potential energy U. Other energy
1joule = 1J = 1 kg·m2 (6.2) s2
units often seen are:
6.1.2 Work
1erg=1g·cm2 =10−7J 1eV=1.60×10−19J s2
When an object moves while a force is being exerted on it, then work is being done on the object by the force.
If an object moves through a displacement d while a constant force F is acting on it, the force does an amount of work equal to
W =F·d=Fdcosφ (6.3)
where φ is the angle between d and F.
Answer:
v=30 m/s
Explanation:
h - height
g - acceleration due to gravity=10
t - time
v- velocity
45 = 5t²
t² = 9
t=3 seconds
v=g×t
v=10×3
v=30 m/s
Answer:
The value is 
Explanation:
From the question we are told that
The width of the slit is 
The distance of the screen from the slit is D = 1.25 m
The width of the central maximum is 
Generally the width of the central maximum is mathematically represented as
Here m is the order of the fringe and given that we are considering the central maximum, the order will be m = 1 because the with of the central maximum separate's the and first maxima
So
=> 
=> 
=>
